Answer:
1. The parabola opens up (in the shape of a "u")
2. The y intercept is a·b
3. The zeros occur at points x = a or b
Step-by-step explanation:
f(x) = y = (x - a)(x - b) = x²-a·x-b·x+a·b
y - a·b = x²-a·x-b·x = x² -x·(a + b)
y - a·b + (a + b)²/4 = x² -x·(a + b) + (a + b)²/4 = (x - (a + b)/2)²
y = (x - (a + b)/2)² + a·b - (a + b)²/4
Hence since the general form of the equation of the parabola is y = a(x - h)² + k
1. Comparing, we have a = +1 which indicates that the parabola opens up
The y intercept is found by placing x = 0 as follows;
y = (0 - (a + b)/2)² + a·b - (a + b)²/4 = a·b
The zeros is the x intercept, where y = 0 which is found as follows;
y = (0 - (a + b)/2)² + a·b - (a + b)²/4 = a·b
0 = (x - (a + b)/2)² + a·b - (a + b)²/4
Hence from the initial equation, f(x) = y = (x - a)(x - b) when y = 0, x = a or b
Hence the zeros occur at points x = a or b.