Answer:
The launch angle should be adjusted to 30.63°
Step-by-step explanation:
The range of a projectile which is the horizontal distance covered by the projectile can be expressed as;
R =(v^2 sin2θ)/g
Where
R = range
v = initial speed
θ = launch angle
g = acceleration due to gravity
For the case above. When the projectile is launched at angle 13° above the horizontal.
θ1 = 13
R1 = (v^2 sin2θ1)/g
R1 = (v^2 sin26°)/g ....1
For the range to double
R2 = (v^2 sin2θ)/g .....2
R2 = 2R1
Substituting R2 and R1
(v^2 sin2θ)/g = 2 × (v^2 sin26°)/g
Divide both sides by v^2/g
sin2θ = 2sin26
2θ = sininverse(2sin26)
θ = sininverse(2sin26)/2
θ = 30.63°
I think it would just be n rad n
Answer:
Step-by-step explanation:
C≈23.25in
It's cicumference is 23.23 inches.
Multiply numerators:
-4*-5=20
Multiply denominators:
9*8=72
20/72= 10/36
10/36= 5/18
Final answer: 5/18
Answer:
10 m²
Step-by-step explanation:
There is no formula to solve this problem
Each square on the grid is 1 unit
- Just count all the squares inside the shape and that will be the area of the figure.
- I counted 6 full squares and 10 half squares which would be 5 whole squares
- Adding those numbers up I have 6 + 5 = 11 ≈10 m²
