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Gnesinka [82]
3 years ago
14

Factor the expression. 10g^3 12g^2 – 15g – 18

Mathematics
2 answers:
damaskus [11]3 years ago
4 0
10g^3 + 12g^2 - 15g - 18 = 2g^2(5g + 6) - 3(5g + 6) = (2g^2 - 3)(5g + 6)

Tanya [424]3 years ago
3 0
10g^3 + 12g^2 - 15g - 18 = 2g^2(5g + 6) - 3(5g + 6) = (2g^2 - 3)(5g + 6)
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Write twelve and five hundred ninety nine thousandths in standard form
MissTica


12,599,000

I think that's how u do it im not sure



8 0
3 years ago
Read 2 more answers
How do you find the degree of an expression?
garri49 [273]

The degree of an expression in more than one variable is the highest sum of the powers of the variables in the terms.

Expression:

An algebraic expression is a combination of constant and variables connected by the signs of fundamental operations.

ex: 2x+5

Degree of an expression:

The degree of an expression in one variable is the highest exponent of the variable in that expression.

Ex:

2x^6 + x^4 + 5

Highest exponent = 6

so degree = 6

The degree of an expression in more than one variable is the highest sum of the powers of the variables.

Ex:

3x^1y^2 + 5x^3y^2 + 5

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Learn more about the expression here:

brainly.com/question/14083225

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4 0
1 year ago
Area of a triangle8ft 4 1/2ft
n200080 [17]
8 x 4.5 = 36
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3 0
3 years ago
If someone could help me that would be great
sasho [114]

Answer:

please mark me as brainlist please

Step-by-step explanation:

Correct option is B)

The circumference of the circle is 96 units.

Therefore, 2π×r=96

⇒r=

2×22

96×7

=15.27 units

Now, in the quadrilateral OLMN,∠OLM+∠LMN+∠MNO+∠NOL=360

o

Given that LM and MN are tangents to the circle, ∠OLM=∠ONM=90

o

∴∠NOL=360−90−90−60=120

o

The length of arc is given by rθ where θ is the angle made by the arc at the centre in radian.

Thus, arc length LN=15.27×

180

120π

=31.98

8 0
3 years ago
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