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elena-s [515]
3 years ago
8

How to do a markup ​

Mathematics
1 answer:
Anarel [89]3 years ago
6 0

divide the amount added to the price by the amount the item costs you to buy to find the markup rate expressed as a decimal.

mark up% = selling price - cost/cost • 100

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The function F(x) is described below. F(x) = 3x + 2 What is the value of F(5)?
Musya8 [376]
f(x)=3x+2 \\  \\ f(5)=3*5+2=15+2=17
6 0
3 years ago
What is the length of line segment c d? round to the nearest tenth. 2.3 cm 4.0 cm 10.7 cm 18.6 cm
ale4655 [162]

The value of CD is 10.7 cm , Option C is the right answer.

<h3>What is a Line Segment ?</h3>

A line segment is a line of fixed measure.

From the figure , as Triangle ABC is a right angled triangle

sin 30 degree = (Perpendicular / Hypotenuse)

∠ B = 30° , AB= 10 cm

sin 30 = AC/10

AC = 5 cm.

To determine CD ,

In Triangle ADC ,

tan 25 = Perpendicular / Base

tan 25 = AC / CD

tan 25 = 5 / CD

CD = 5 / 0.4663

CD = 10.7 cm

Therefore the value of CD is 10.7 cm , Option C is the right answer.

To know more about Line Segment

brainly.com/question/25727583

#SPJ1

3 0
2 years ago
NEED ASAP <br> NO LINKS PLS <br> WILL MARK BRAINLIEST
pickupchik [31]

Answer:1.4348e-5 for dimensions and area is 160,000 sq ft. but thats only the first tree one...only one i can do without my brain giving out..good luck

Step-by-step explanation:

6 0
3 years ago
Find the area of rectangle, where length is 15 cm and breadth is 7 cm.​
Varvara68 [4.7K]

Question :-

  • Find the Area of Rectangle , where the Lenght is 15 cm and its Breadth is 7 cm .

Answer :-

  • Area of Rectangle is 105 cm² .

\rule {195pt} {2pt}

Diagram :-

\sf{15 \: cm} \\ \quad \quad  \begin{gathered}\begin{gathered} \boxed{\begin{array}{c} \\   \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \\  \\  \\ \end{array}}  \:  \:  \sf {7 \: cm}\end{gathered}\end{gathered}

\rule {195pt} {2pt}

Solution :-

\quad \quad » As per the provided information in the given question, we have been given that the Length of Rectangle is 15 cm . It's Breadth is given as 7 cm . And, we have been asked to calculate the Area of Rectangle.

For calculating the Area of Rectangle , we will use the Formula :-

  • \sf {Area \: of \: Rectangle \: = \: Length \: \times \: Breadth}

Therefore , by Substituting the given values in the above Formula :-

\Longrightarrow \: \: \: \sf {Area \: of \: Rectangle \: = \: Length \: \times \: Breadth} \\

\Longrightarrow \: \: \: \sf {Area \: of \: Rectangle \: = \: 15 \: \times \: 7}

\Longrightarrow \: \: \: \sf {Area \: of \: Rectangle \: = \: 105}

Hence :-

  • Area of Rectangle = 105 cm² .

\underline {\rule {195pt} {4pt}}

Additional Information :-

\begin{gathered}\begin{gathered}\boxed{\begin{array}{c} \\ \underline{ { \textbf {\textsf \red{ \dag \:  \: More \: Formulas \:  \:  \dag}}}} \\  \\  \\  \footnotesize \bigstar  \:  \bf{Area \: _{Square} = Side \times Side}  \\  \\  \\   \footnotesize\bigstar  \:  \bf{Area \: _{Rectangle} = Lenght \times Breadth} \\  \\  \\  \footnotesize \bigstar \:  \bf{Area \: _{Triangle} =  \frac{1}{2} \times Base \times Height } \\  \\  \\  \footnotesize \bigstar \:  \bf{Area \: _{Parallelogram} = Base \times Height} \\  \\  \\  \footnotesize \bigstar \:  \bf{Area \: _{Trapezium} =  \frac{1}{2} \times [ \: A + B \: ] \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf {Area \: _{Rhombus} = \frac{1}{2} \times Diagonal \: 1 \times Diagonal \: 2}\end{array}}\end{gathered}\end{gathered}

5 0
2 years ago
Read 2 more answers
Solve the system of equations using the linear combination method. {5m+3n=41 {3m−6n=9 Enter your answers in the boxes. m = n =
Masja [62]
These are linear equations that can be solved simultaneously;
5m+3n=41
3m-6n=9   (multiplying the first equation by 3 and the second by 5)

15m+9n=123
15m-30n= 45 (subtracting the two equations)
         39n = 78
             n = 2, 
and for m, 3m = 9+6(2)
                        = 21
                     m = 7
Therefore, n=2 and m=7
8 0
4 years ago
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