Let the second score = x
⇒ second score = x
<span>the first is 14 points more than the second
</span>⇒ first score = x + 14
<span>the sum of the first two is 6 more than twice the third
</span>⇒ third score = 1/2 (x + x + 14 - 6) = x + 4
<span>The sum of a student's three score is 246
</span>⇒ x + (x + 14) + (x + 4) = 246
<span>
Solve x:
</span>x + x + 14 + x + 4 = 246
3x + 18 = 246
3x = 228
x = 76
second score = x = 76
first score = x + 14 = 76 + 14 = 90
Answer: 90
They can not, there are only 2 sides and they probably flipped it different ways. They got 'lucky'.
Answer:
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Coordinates (x, y)
- Midpoint Formula:
Step-by-step explanation:
<u>Step 1: Define</u>
Point (2, 9)
Point (8, 1)
<u>Step 2: Identify</u>
(2, 9) → x₁ = 2, y₁ = 9
(8, 1) → x₂ = 8, y₂ = 1
<u>Step 3: Find Midpoint</u>
Simply plug in your coordinates into the midpoint formula to find midpoint
- Substitute in points [Midpoint Formula]:
- [Fractions] Add:
- [Fractions] Divide:
Answer:
its 34
Step-by-step explanation:
its half of the center angles
Answer:
At the end of the day 797 lockers were closed.
Step-by-step explanation:
So first of all you need to find out how many even numbers there are from 1-900 (which is 450) so you know that 450 are open. In the 3 multiplication tables every second number is even so you know that half of the 450 lockers that was opened was closed again: this meant that 225 lockers remained open.
You also know that every number in the 4 multiplication tables is the second number in the 2 multiplication tables so half of them are closed but you also know that the 900th locker was opened so now you have 113.
So to conclude you do 900-113 which gives you 797 (this is because 113 is the amount of lockers that is open)
