Answer:
42 child and 70 adult
Step-by-step explanation:
Let a = number of adult tickets
c = number of child tickets
a+c = 112
2.25a + 1.75c = 231
Solve the first equation for a
a = 112-c
Substitute this into the second equation
2.25(112-c) + 1.75c = 231
Distribute
252 - 2.25c +1.75c = 231
Combine like terms
252 -.5c = 231
Subtract 252 from each side
252-252 -.5c = 231-252
-.5c = -21
Divide each side by -.5
-.5c/-.5 = -21/ -.5
c = 42
Now can find a
a = 112-c
a = 112-42
a = 70
Answer:
$1000
Step-by-step explanation:
We can form an equation for Clayton's account: C = 500 + 10x
We can form an equation for Clayton's account: J = 400 +12x
(where x is the number of days)
When the two accounts will contain the same amount, it means: C = J
<=> 500 + 10x = 400 +12x
<=> x =50
After 50 days, there accounts will be balance. Then, we substitue x into any of the 2 equation to find out the amount: 500 + 10(50) = $1000
The slope is 4 and the Y-Intercept is 0.
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