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GaryK [48]
3 years ago
5

The formula below gives D, the demand for concert tickets when the price of each ticket is p dollars. 

Mathematics
2 answers:
yarga [219]3 years ago
5 0
D(p) = 2000-4p-p2

if p=15 then 2000-60-30 which = 1920 :)
Vlada [557]3 years ago
4 0
Hey and I think it's D
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The volume of a cone varies jointly with the area of the base and the height. When the area of the base is 27 cm2 and the height
Tomtit [17]
Cone=cup:
V=124<span>cm^3.
h=12cm
V=Bh
P=r</span>^2π+rsπ:
B=r^2π
B=V/h=124/12=10,3cm^2
r^2=B/π
r=√(B/π)=1,81 cm
S=√(r^2+h^2)=√(12^2+1.81^2)=√(144+3,28)=12,13 cm
P=r^2π+rSπ=3,28*3,14+1,81*12,13*3,14=10,29+68,93=79,22 cm^2
3 0
2 years ago
A bakery sold 27 mocha cupcakes in a day, which was 9% of the total number of
Sidana [21]

Answer:

300 cupcakes

Step-by-step explanation:

27 = .09c

c =  \frac{27}{.09}  =  \frac{2700}{9}  = 300

8 0
2 years ago
stans cookie recipe makes 24 cookies and calls for exactly 384 sprinkles. he is wondering how many sprinkles (p) he will need to
Angelina_Jolie [31]

Answer:

960 sprinkles

Step-by-step explanation:

If 24 cookies call for EXACTLY 384 sprinkles, then 16 sprinkles fit on each cookie. 384/24 = 16

If 16 sprinkles fit on each cookie, 16 cookies on 60 cookies would be 960.

60 x 16 = 960

4 0
2 years ago
Find the surface area of x^2+y^2+z^2=9 that lies above the cone z= sqrt(x^@+y^2)
Mashcka [7]
The cone equation gives

z=\sqrt{x^2+y^2}\implies z^2=x^2+y^2

which means that the intersection of the cone and sphere occurs at

x^2+y^2+(x^2+y^2)=9\implies x^2+y^2=\dfrac92

i.e. along the vertical cylinder of radius \dfrac3{\sqrt2} when z=\dfrac3{\sqrt2}.

We can parameterize the spherical cap in spherical coordinates by

\mathbf r(\theta,\varphi)=\langle3\cos\theta\sin\varphi,3\sin\theta\sin\varphi,3\cos\varphi\right\rangle

where 0\le\theta\le2\pi and 0\le\varphi\le\dfrac\pi4, which follows from the fact that the radius of the sphere is 3 and the height at which the sphere and cone intersect is \dfrac3{\sqrt2}. So the angle between the vertical line through the origin and any line through the origin normal to the sphere along the cone's surface is

\varphi=\cos^{-1}\left(\dfrac{\frac3{\sqrt2}}3\right)=\cos^{-1}\left(\dfrac1{\sqrt2}\right)=\dfrac\pi4

Now the surface area of the cap is given by the surface integral,

\displaystyle\iint_{\text{cap}}\mathrm dS=\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}\|\mathbf r_u\times\mathbf r_v\|\,\mathrm dv\,\mathrm du
=\displaystyle\int_{u=0}^{u=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}9\sin v\,\mathrm dv\,\mathrm du
=-18\pi\cos v\bigg|_{v=0}^{v=\pi/4}
=18\pi\left(1-\dfrac1{\sqrt2}\right)
=9(2-\sqrt2)\pi
3 0
2 years ago
Please help me with this question.
stiv31 [10]
9 - 1/2 is the answer
3 0
2 years ago
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