-5-(15y-1) = 2(7y-16) - y // question
-5-15y+1 = 14y-32-y // distribute
-15y - 4 = 13y - 32 // subtract
-28y = -28 // divide
y = 1
<h3>Answer:</h3>
m= -3/2
<h3>Step by step:</h3>
m=y1-y2/x1-x2 = 4-7/4-2 = -3/2
Answer:
X density = fXpxq and
Y" =InpXq
Now to find Y density FYpyq interms of the density of X we compare the density of X with Y"
fX = In
And PXq =pxq
Thus replacing x with y,
PXq = pyq
(a) Hence the density of Y is FYpyq
(b) at p0, fYpyq =fYp0q= 0
At 5s, FYpyq =5
Answer:
R = (- 3.5, - 7 )
Step-by-step explanation:
Using the Section formula
=
=
=
= - 3.5
=
=
=
= - 7
Thus coordinates of R = (- 3.5, - 7 )
He spent 560. Just multiply 70 with 8