it takes 5 seconds to reach a height of 40 ft. and It takes 2.5 seconds to reach maximum height.
Let h(t) represent the height of the ball at time t.
Given that the height is given by:
h(t) = -16t² + 80t + 40
1) For the ball to reach a height 0f 40 ft, h(t) = 40, hence:
40 = -16t² + 80t + 40
16t² - 80t = 0
t(t - 5) = 0
t = 0 or t = 5
Hence it takes 5 seconds to reach a height of 40 ft.
2) The maximum height is at h'(t) = 0,
h'(t) = -32t + 80
-32t + 80 = 0
32t = 80
t = 2.5
It takes 2.5 seconds to reach maximum height.
Find out more at: brainly.com/question/11535666
Answer:
(-2,3)
Step-by-step explanation:
For the point to be 2/3 of the way; it means it divides AB into the ratio 2 to 1
Now, we can use the internal section formula to get the coordinates of this point
(x,y) = (nx1 + mx2)/(m + n), (ny1 + my2)/(m + n)
where (m,n) = (2,1)
(x1,y1) = (-4,-1)
(x2,y2) = (5,5)
(x,y) = (1(-4) + 2(-1)/(1+2), (1(-1)+2(5)/(1+2)
(x,y) = (-4-2)/3, (-1 + 10)/3
(x,y) = (-2,3)
Answer: 4th graph
Step-by-step explanation:
