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FromTheMoon [43]
3 years ago
12

Hi, prove that (AXB).(CXD)+(BXC).(AXD)+(CXA).(BXD)=0

Mathematics
1 answer:
slava [35]3 years ago
5 0
No.i will not prove that.
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Let n be a natural number. Show that 3 | n3 −n
Vladimir [108]
Let n=1. Then n^3-n=1^3-1=0. By convention, every non-zero integer n divides 0, so 3\vert n^3-n.

Suppose this relation holds for n=k, i.e. 3\vert k^3-k. We then hope to show it must also hold for n=k+1.

You have

(k+1)^3-(k+1)=(k^3+3k^2+3k+1)-(k+1)=(k^3-k)+3(k^2+k)

We assumed that 3\vert k^3-k, and it's clear that 3\vert 3(k^2+k) because 3(k^2+k) is a multiple of 3. This means the remainder upon divides (k+1)^3-(k+1) must be 0, and therefore the relation holds for n=k+1. This proves the statement.
4 0
2 years ago
Solve for x Show your work
telo118 [61]

Answer:

x = 12

Step-by-step explanation:

To solve this and show your work, you have to start of with the equation (3x - 6) = 30.

You then have to add 6 to both sides like this:

(3x - 6) = 30 \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \: + 6  \:  \:  \:   \:  \:   + 6

So then the 6 is cancelled out, and you are left with

3x = 36.

Now you just have to divide both sides by 3 like this:

\frac{3x}{3}  =  \frac{36}{3}

Which cancels 3 out, and you are left with

x = 12.

4 0
3 years ago
Need help please?????
Fantom [35]
Its C, sorry for the kinda late answer
7 0
3 years ago
Which equation can be used to solve for x in the triangle below?
belka [17]

Using the cosine rule, the equation to use to solve for x is: x = √(4.0² + 4.7² − 2(4.0)(4.7) × cos(41)) ≈ 3.1 cm.

<h3>How to Use the Cosines Rule to Solve a Triangle?</h3>

The cosine rule is given as, c = √(a² + b² − 2ab × cos(C))

Given the following:

  • c = x = ?
  • a = 4.0 cm
  • b = 4.7 cm
  • C = 41°

Plug in the values:

x = √(4.0² + 4.7² − 2(4.0)(4.7) × cos(41))

x ≈ 3.1 cm

Learn more about the cosine rule on:

brainly.com/question/23720007

#SPJ1

4 0
1 year ago
Amber is an American teaching English in China, and she currently has 35,000
cupoosta [38]
The awnser is A because you just divid it
6 0
3 years ago
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