Hi, prove that (AXB).(CXD)+(BXC).(AXD)+(CXA).(BXD)=0
1 answer:
You might be interested in
Answer:
b
Step-by-step explanation:
The area of a square = s² ← s is the length of the side, hence
s² = 800 ( take the square root of both sides )
s = ≈ 28.28
28.28 is between 28 and 29 → b
<h2>>> Answer </h2>
_______
C. g(x) = (x - 4)²
Soo, graph in the picture.