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Work out the size of the interior angle of a regular 18-sided polygon.

qaws [65]

Answer:

160°

Step-by-step explanation:

The formula below gives the measure of an interior angle of a regular polygon of n sides.

[(n - 2)180]/n

[(18 - 2)180]/18

16(10)

160

Answer: 160°

4 0

2 years ago

A and B are points on a line that has the slope 2. The abscissa of B exceeds the abscissa of A by 3.5. State the relationship of

Troyanec [42]

Answer:

The ordinate of B exceeds the ordinate of A by 7

Step-by-step explanation:

Let

A(x1,y1),B(x2,y2)

where

x1 is the abscissa of A

x2 is the abscissa of B

y1 is the ordinate of A

y2 is the ordinate of B

we know that

$m=\frac{y2-y1}{x2-x1}$

$m=2$

so

$2=\frac{y2-y1}{x2-x1}$ -----> equation A

$x2=x1+3.5$ ----> equation B

substitute equation B in equation A

$2=\frac{y2-y1}{x1+3.5-x1}$

$2=\frac{y2-y1}{3.5}$

$7=y2-y1$

$y2=y1+7$

therefore

The ordinate of B exceeds the ordinate of A by 7

6 0

3 years ago

Find the area of the part of the plane 3x 2y z = 6 that lies in the first octant.

gavmur [86]

The area of the part of the plane 3x 2y z = 6 that lies in the first octant is mathematically given as

A=3 √(4) units ^2

<h3>What is the area of the part of the plane 3x 2y z = 6 that lies in the first octant.?</h3>

Generally, the equation for is mathematically given as

The Figure is the x-y plane triangle formed by the shading. The formula for the surface area of a z=f(x, y) surface is as follows:

$A=\iint_{R_{x y}} \sqrt{f_{x}^{2}+f_{y}^{2}+1} d x d y(1)$

The partial derivatives of a function are f x and f y.

$\begin{aligned}&Z=f(x)=6-3 x-2 y \\&=\frac{\partial f(x)}{\partial x}=-3 \\&=\frac{\partial f(y)}{\partial y}=-2\end{aligned}$

When these numbers are plugged into equation (1) and the integrals are given bounds, we get:

$&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{(-3)^{2}+(-2)^2+1dxdy} \\\\&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{14} d x d y \\\\&=\sqrt{14} \int_{0}^{2}[y]_{0}^{3-\frac{3}{2} x} d x d y \\\\&=\sqrt{14} \int_{0}^{2}\left[3-\frac{3}{2} x\right] d x \\\\$

$&=\sqrt{14}\left[3 x-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3.2-\frac{3}{2} \cdot \frac{1}{2} \cdot 3^{2}\right] \\\\&=3 \sqrt{14} \text { units }{ }^{2}$

In conclusion, the area is

A=3 √4 units ^2

Read more about the plane

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5 0

1 year ago

if pears cost 0.92 cents per pound and apples cost $1.10 if someone was to bring 3.75 pounds of pears and 2.1 pounds of apples h

GarryVolchara [31]

They paid $5.67 for the pears and apples.

3 0

2 years ago

Marisa can buy 3 oranges for 1.35 dollars ,four oranges for $1.80 or five oranges for $2.25 per second by 10 oranges for a price

scZoUnD [109]

3 oranges= $1.35, so one orange cost $0.45
4 oranges= $1.80, one orange cost $0.45
5 oranges= $2.25, one orange cost $0.45
If one orange cost $0.45, then ten cost $4.50 ($0.45*10)

If you were to buy ten oranges are $4.25, this would make each orange $0.425 ($0.43 rounded).

This means that if you were to buy ten oranges, it would be cheaper to buy ten for $4.25, instead of buying two lots of 5 for $2.25 each.

Hope this helps :)

3 0

2 years ago