Divide by the coefficient of e^2, then take the square root.
e^2 = 49/(9f)
e = ±7/(3√f) = ±(7√f)/(3f)
The 3rd selection is appropriate:
e=±(7√f)/(3f)
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When written in plain text (not typeset), any denominator containing arithmetic must be enclosed in parentheses. When the expression is typeset, the surd and the division bar do the grouping for you.
Answer:

Step-by-step explanation:
Hello,
(1) 2x + 4y + z = 3
(2) x - 2y - 3z = 4
(3) x + y - z = -1
From (3) we can write z = x + y + 1 and we replace in (1)
2x + 4y + x + y + 1 = 3 <=> 3x + 5y = 3-1 =2
(1') 3x + 5y = 2
and we replace in (2)
x - 2y -3(x+y+1) = 4 <=> -2x -5y -3 = 4 <=> -2x -5y = 4 + 3 = 7
(2') -2x - 5y = 7
(1') + (2') gives
3x - 2x + 5y - 5y = 2 + 7 = 9
x = 9
we replace in (1')
3*9 + 5y = 2 <=> 27 + 5y = 2 <=> 5y = 2-27 = -25 <=> y = -25/5 = -5
y = -5
and then in (3)
9 - 5 - z = -1 <=> 4 - z = -1 <=> z = 4 + 1 = 5
z = 5
hope this helps
Answer:
-12
Step-by-step explanation:
I am assuming that you want (f*g)(4), which is the product of f and g at x = 4.
If this is actually the case, then one way to evaluate (f*g)(4) is to find f(4) and g(4) separately and then multiply the results together. This gives us
f(4)*g(4) = (8 + 4)*(-4 + 3) = -12
That's correct because 13•-1•-5=-18 so what is the question
D. f(x)= x*-9x^o+2x^2-4x+10