All categories

2 years ago

How to solve the equation and rounding the answer to four decimal places

Mathematics

1 answer:

pogonyaev2 years ago

5 0

The answer is 0.5778 or 0.578 rounded

You might be interested in

Perform the indicated operation. Be sure the answer is reduced.

avanturin [10]

<h3>Given Equation:-</h3>

$\boxed{ \rm \frac{4x^{2}y^{3}z}{9} \times \frac{45y}{8 {x}^{5} {z}^{5} }}$

<h3>Step by step expansion:</h3>

$\dashrightarrow \sf\dfrac{4x^{2}y^{3}z}{9} \times \dfrac{45y}{8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{ \cancel4x^{2}y^{3}z}{9} \times \dfrac{45y}{ \cancel8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{9} \times \dfrac{45y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{ \cancel9} \times \dfrac{ \cancel{45}y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{0}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5 - 2} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z}{1} \times \dfrac{5y}{2{x}^{3} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z {}^{0} }{1} \times \dfrac{5y}{2{x}^{3} {z}^{3 - 1} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}}{1} \times \dfrac{5y}{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y \times {y}^{3} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y {}^{0} \times {y}^{3 + 1} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5 \times {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \bf \dfrac{5 {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\therefore \underline{ \textbf{ \textsf{option \red c \: is \: correct}}}$

8 0

2 years ago

A triangle has vertices (-1,2), (3,1), and (7,2). What is the approximate perimeter of the triangle? Round the answer to the nea

marin [14]

The perimeter is 16.2. Let me know if you need me to show you how I got this

4 0

2 years ago

Read 2 more answers

The horizontal distance between two towers is 70m. The angle of depression of the top of the first tower when seen from the top

lana66690 [7]

As shown in the image, we have a 30 degree angle and x, which is what we want. By doing tan30, we can find x, so tan30=x/70 and 70*tan30=x= 70*sqrt(3)/3. 120-x=height of first tower = 120-(70*sqrt(3)/3) = roughly 79.59

7 0

3 years ago

Find the value of 26/45 times 5/53 times 28/13 please show fingures and work

hjlf

$\bf \cfrac{\stackrel{2}{~~\begin{matrix} 26 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}{\underset{9}{~~\begin{matrix} 45 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\cdot \cfrac{~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{53}\cdot \cfrac{28}{~~\begin{matrix} 13 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies \cfrac{2\cdot 28}{9\cdot 53}\implies \cfrac{56}{477}$

3 0

3 years ago

Which of the following is an even function?

Lelechka [254]

Answer:

Step-by-step explanation:

3 0

2 years ago