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4 years ago

Which of the following polynomials is in standard form?

Mathematics

2 answers:

Stels [109]4 years ago

7 0

D. f(x)= x*-9x^o+2x^2-4x+10

g100num [7]4 years ago

5 0

Answer:

Step-by-step explanation:

None of these are in standard form. In standard form the powers of x are arranged in descending order, which is not the case here. Also, all terms containing the same power of x (such as x - 4x - 9x) should be simplified into ONE term with ONE coefficient.

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Ms. Owens has some pencils . She give 5 of them away. Now she has 13 pencils left. How many pencils did she start with?

Anastaziya [24]

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3 years ago

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GarryVolchara [31]

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3 years ago

Nine students made models of mars and its moons. The answer is 18. What’s the question?

VashaNatasha [74]

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3 years ago

Please help ive been stuck!!

Kobotan [32]

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3 years ago

Write each expression as an algebraic (nontrigonometric) expression in u, u > 0.

max2010maxim [7]

Answer:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

Step-by-step explanation:

We want to write the trignometric expression:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0$

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

$\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)$

Take the secant of both sides:

$\displaystyle \sec(\theta)=\frac{u}{10}$

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

$\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}$

By substitutition:

$\displaystyle= \sin(2\theta)$

Using an double-angle identity:

$=2\sin(\theta)\cos(\theta)$

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

$\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)$

Simplify. Therefore:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

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3 years ago