The induced-fit model includes the change in the conformational site of the substrate and enzyme. It is done till the enzyme completely binds the substrate. This will then activates the enzyme to perform its work.
<h3>What is induced fit theory?</h3>
Induced fit theory or model suggest that the activation site of enzymes and the binding site of substrates undergo some conformational changes to fit into each other.
This binding results in activation of the enzyme and as the enzyme has a three-dimensional tertiary structure, this would help it to get fitted into the substrate.
Thus, with reference to the induced fit model tertiary structure of enzyme facilitates its function as a biological catalyst.
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Answer:
The answer is false. The correct answer is cerebral aqueduct.
Explanation:
Because the foramen is the area that connects the third ventricle of the brain to the two lateral ventricles.
The canal connecting the third and fourth ventricles is called cerebral aqueduct.
Hypersecretion of the population from the anterior pituitary gland causes the condition of galactorrhea.
Prolactin is another name is called luteotropin and its main function is to enable mammals mostly female to produce milk. The pituitary gland secretes it in response to mating, estrogen treatment, ovulation, nursing and eating.
The pituitary gland is attached to the hypothalamus by a short stalk. The pituitary gland has two major parts.
(i) An anterior lobe
(ii) Posterior lobe.
The pituitary gland is controlled by hormones and neurons that comes in the hypothalamus where it acts as a link between brain and endocrine system, and hypothalamus is the endocrine gland itself. Hypothalamus has neurons which regulate secretion of anterior lobe hormones by secreting inhibit and releasing hormones. Every hormone produced by anterior lobe has a releasing hormone.
Prolactin and growth hormones have inhibiting hormone. Releasing hormone helps in stimulating production and it releases hormones from the anterior lobe.
Answer:
See the answer below
Explanation:
Let the disorder be represented by the allele a.
Since the disease is an autosomal recessive one, affected individuals will have the genotype aa and normal individuals will have the genotype Aa or AA.
Since the four adults are carriers, their genotypes would be Aa.
Aa x Aa
Progeny: AA 2Aa aa
Probability of being affected = 1/4
Probability of being a carrier = 1/2
Probability of not being affected = 3/4
(a) The chance that the child second child of Mary and Frank will have alkaptonuria = 1/2
(b) The chance that the third child of Sara and James will be free of the condition = 3/4
(c)
(d) If someone has no family history of the disorder, their genotype would be AA.
AA x aa
4 Aa
<em>The chance that a child with alkaptonuria will have an offspring with alkaptonuria if the child's mate has no family history </em>= 0
(e)
(f) <em>The chance that a child with alkaptonuria will have an offspring with alkaptonuria if the child's mate has no family history</em> = 0
