<u>the correct question is</u>
The denarius was a unit of currency in ancient rome. Suppose it costs the roman government 10 denarii per day to support 4 legionaries and 4 archers. It only costs 5 denarii per day to support 2 legionaries and 2 archers. Use a system of linear equations in two variables. Can we solve for a unique cost for each soldier?
Let
x-------> the cost to support a legionary per day
y-------> the cost to support an archer per day
we know that
4x+4y=10 ---------> equation 1
2x+2y=5 ---------> equation 2
If you multiply equation 1 by 2
2*(2x+2y)=2*5-----------> 4x+4y=10
so
equation 1 and equation 2 are the same
The system has infinite solutions-------> Is a consistent dependent system
therefore
<u>the answer is</u>
We cannot solve for a unique cost for each soldier, because there are infinite solutions.
Answer:
41.9 %
Step-by-step explanation:
when you look at the to numbers you will see that the two has a 41.9 % difference.
Answer:
D) $8.20
Step-by-step explanation:
82 x 0.1 = 8.2
Hello from MrBillDoesMath!
Answer:
One solution (z = -1)
Discussion:
-2(z+3)-z=-z-4(z+2) =>
-2z -6 -z = -z -4z - 8 =>
-3z -6 = -5z -8 => add 6 to both sides
-2z = -5z -2 => add 5z to both sides
3z = -5z +5z -3 =>
3z = -3 =>
z = -1
Thank you,
MrB
Answer:
40
Step-by-step explanation:
So split it into two shapes. Two rectangles.
Rectangle 1 = 4 * 5 = 20
Rectangle 2 = 2 * 10 = 20
20 + 20 = 40
