X^4+ 3x^3+4x^2-8 | x+2 = x^3+x^2+2x-4
-x^4-2x^3
-----------------------
x^3+4x^2-8
-x^3-2x^2
-------------------------
2x^2-8
-2x^2-4x
--------------
-4x-8
4x+8
----------------------------
/ /
is a factor because (x+2)(x^3+x^2+2x-4)=x^4+3x^3+4x^2-8
Answer:
The correct answer is The second table.
Step-by-step explanation:
1x5= 5
2x5= 10
3x5= 15
4x5= 20
5x5= 25
Hope this helps!! (:
Step-by-step explanation:
I assume AB is supposed to be a straight line. yes ?
in that case please remember that all angles on top of a line (and then again below a line) must sum up to 180 degrees (this is what it takes to flip a "stick" on that line from left to right).
so, COD covers already 90 degrees of these 180.
that means AOD + BOC = 180 - 90 = 90 degrees.
now we know that the 2 angles are in the ratio of 1:5.
that means that BOC is 5 times as large as AOD.
and we can be more direct :
since the 2 angles are in the ratio 1:5 we are actually splitting the remaining 90 degrees into 6 parts (5+1).
and BOC gets then 5 of these 6 parts, and AOD gets the remaining 1 part.
so,
90/6 = 15
therefore, one of these parts is 15 degrees.
so, we know AOD = 15 degrees.
BOC = 5×15 = 75 degrees
or simply 90 - 15 = 75 degrees
C.) is the answer, I think
First of all, we need to know the coordinate of ABCD and A'B'C'D', so the coordinate of ABCD will be:
A(-3,5)
B(-1,2)
C(-2,-1)
D(-5,-3)
Then, coordinate of new figure will be:
A'(-7,8)
B'(-5,5)
C'(-6,2)
D'(-9,0)
Next,
Let's try all the translations:
(x,y) to (x+4,y+3)
A(-3,5) to A'(-3+4, 5+3)
A(-3,5) to A'(1,8)
Which is not right because A' need to be (-7,8)
(x,y) to (x-4,y+3)
A(-3,5) to A'(-3-4,5+3)
A(-3,5) to A'(-7,8)
B(-1,2) to B'(-1-4,2+3)
B(-1,2) to B'(-5,5)
C(-2,-1) to C'(-2-4,-1+3)
C(-2,-1) to C'(-6,2)
D(-5,-3) to D'(-5-4,-3+3)
D(-5,-3) to D'(-9,0)
Yay, we found the answer. As a result, (x,y) to (x-4,y+3) is your final answer. Hope it help!
