Create an application that lets the user enter the food charge for a meal at a restaurant. When a button is clicked, the applica
tion should calculate and display the amount of a 15 percent tip, 7 percent sales tax, and the total of all three amounts.
1 answer:
Answer:
Public Class Form1
Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click
Dim foodCharge, tax, tip, totalCharge As Double
foodCharge = Val(TextBox1.Text)
tax = 0.07 * foodCharge
tip = 0.15 * 100
totalCharge = foodCharge + tax + tip
Label5.Text = tax
Label6.Text = tip
Label7.Text = totalCharge
End Sub
End Class
Explanation:
- This is implemented using Visual Basic programming language
- Firstly we declared all the variables using DIM key word
- Then the calculation for each variable is done according to the specification of the question
- On the form (See attached Image) the controls for receiving the user input is created as well as the controls for the output.
- See the attached sample run below:
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Answer:
Check the explanation
Explanation:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#define MAX_LIMIT 50
int checkComma(char *input)
{
int flag = 0;
for(int i = 0; i < strlen(input); i++)
{
if(input[i] == ',')
{
flag = 1;
break;
}
}
return flag;
}
int main(void)
{
char input[MAX_LIMIT];
char *words[2];
char delim[] = ", ";
printf("\n");
do
{
printf("Enter input string: ");
fgets(input, MAX_LIMIT, stdin);
size_t ln = strlen(input) - 1;
if (*input && input[ln] == '\n')
input[ln] = '\0';
if(strcmp(input, "q") == 0)
{
printf("Thank you...Exiting\n\n");
exit(1);
}
else
{
if(checkComma(input) == 0)
{
printf("No comma in string.\n\n");
}
else
{
char *ptr = strtok(input, delim);
int count = 0;
while(ptr != NULL)
{
words[count++] = ptr;
ptr = strtok(NULL, delim);
}
printf("First word: %s\n", words[0]);
printf("Second word: %s\n\n", words[1]);
}
}
}while(strcmp(input, "q") != 0);
return 0;
}
Kindly check the attached image below for the output.
