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trapecia [35]
3 years ago
12

A ___ is a node (or a device) that connects two different networks together and allows them to communicate.

Computers and Technology
1 answer:
stellarik [79]3 years ago
7 0

Answer:

The answer is Hub

Explanation:

A hub, also called a network hub, is a common connection point for devices in a network. Hubs are devices commonly used to connect segments of a LAN. The hub contains multiple ports. When a packet arrives at one port, it is copied to the other ports so that all segments of the LAN can see all packets.

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What are the characteristics of a good text-based adventure game? In other words, what are some features that should be in the g
Degger [83]

Answer:

spelling and good format

Explanation:thats all i know

8 0
2 years ago
Write a class called SimpleSquare that has the following properties: - public int field called num - private int field called sq
mezya [45]

Answer:

public class SimpleSquare{

   public int num;

   private int square;

   

   public SimpleSquare(int number){

       num = number;

       square = number * number;

   }

   

   public int getSquare(){

       return square;

   }    

}

Explanation:

*The code is in Java.

Create a class called SimpleSquare

Declare two fields, num and square

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Since the square is a private field, I also added the getSquare() method which returns the value of the square.

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2 years ago
Antiglare screens are sometimes called ____.
yaroslaw [1]
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8 0
3 years ago
The "fathers of the internet" are vinton cerf and ________.
Harrizon [31]
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8 0
3 years ago
Write the program to solve quadratic equations, but if the discriminant is negative, output
Firdavs [7]

Answer:

PROGRAM  QuadraticEquation Solver

  IMPLICIT  NONE

REAL :: a, b, c ;

  REA :: d ;

  REAL  :: root1, root2 ;

//read in the coefficients a, b and c

  READ(*,*)    a, b, c  

  WRITE(*,*)   'a = ', a

  WRITE(*,*)   'b = ', b

  WRITE(*,*)    'c = ', c

  WRITE(*,*)

// computing the square root of discriminant d

  d = b*b - 4.0*a*c

  IF (d >= 0.0) THEN              //checking if it is solvable?

     d     = SQRT(d)

     root1 = (-b + d)/(2.0*a)     // first root

     root2 = (-b - d)/(2.0*a)     // second root

     WRITE(*,*)  'Roots are ', root1, ' and ', root2

  ELSE                            //complex roots

     WRITE(*,*)  'There is no real roots!'

     WRITE(*,*)  'Discriminant = ', d

  END IF

END PROGRAM  QuadraticEquationSolver

8 0
3 years ago
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