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ozzi
3 years ago
9

Multiply the following polynomials and enter the MISSING LINEAR Term :

Mathematics
2 answers:
lina2011 [118]3 years ago
8 0
- 15y4 - 33y3 + y2 + 8 = - 33y3 + 3y2
- 15y4 - 2y3 + 8
Inessa05 [86]3 years ago
6 0

We are given

-3y(5y^3+11y^2-y+8)=-15y^4-33y^3+3y^2-........?........

Firstly, we will simplify left side

and then we can compare it with right side

Left side:

-3y(5y^3+11y^2-y+8)

We can distribute -3y

=-3y*5y^3+-3y*11y^2--3y*y+-3y*8

now, we can simplify it

=-15y^4-33y^3+3y^2-24y

now, we can compare it with right side

we can see that only last term is missing

so, there should be -24y in last term

so, we get

-3y(5y^3+11y^2-y+8)=-15y^4-33y^3+3y^2-24y.................Answer

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In reciprocal is the denominator one unit
docker41 [41]
Not always if you're saying it will always be something like 1/2 becomes 2/1 with a unit of one. It's just flipped, so 2/6 will be 6/2, 4/5 becomes 5/4, 22/16 becomes 16/22 etc. That is all there is to it. Make sure you simplify your answers.
5 0
3 years ago
Which of the following has a constant of proportionality of 2? A) y = 2x B) y = x + 2 C) 2y = x D) y + 2 = 2x
Setler [38]

The correct answer is A.


You have direct variation if x and y are modeled by the equation


y = mx


In this case, m is the constant of proportionality. So, if the constant has to be 2, the equation becomes


y = 2x


A side note: Actually, option C has a constant of proportionality of two as well, except the roles of x and y are interchanged. I chose option A because usually you want the y = mx form, but the names of the variables are obviously meaningless.

5 0
3 years ago
Read 2 more answers
1/6d + 2/3 = 1/4(d-2) how to solve
natita [175]
Greetings!

Solve for d.
1/6d + 2/3 = 1/4(d-2)
Distribute the Parenthesis.
1/6d + 2/3 = 1/4*d+1/4*-2
1/6d + 2/3 = 1/4d+1/4*-2/1
1/6d + 2/3 = 1/4d-2/4
Reduce.
1/6d + 2/3 = 1/4d-1/2
Add -2/3 to both sides.
(1/6d + 2/3)+(-2/3)=(1/4d-1/2)+(-2/3)
Simplify.
1/6d=1/4d-3/6-4/6
1/6d=1/4d-7/6
Add -1/4d to both sides.
(1/6d)+(-1/4d)=(1/4d-7/6)+(-1/4d)
Simplify.
2/12d)-3/12d=-7/6
-1/12d=-7/6
Divide both sides by -1/12.
(-1/12d)/-1/12=(-7/6)/-1/12
Simplify.
d=(-7/6)*-12/1
d=84/6
Reduce.
d=14/1
d=14

Hope this helps.
-Benjamin
7 0
3 years ago
A circle is centered at the origin and contains the point (-6, -8). What is the area of this circle?​
gogolik [260]

Answer:

314 units²

Step-by-step explanation:

Centre of the circle = (0, 0)

Another point on the circle = (-6, -8)

\text {Radius = }\sqrt{(0 - (-6))^2 + (0- (-8))^2}

\text {Radius = }\sqrt{6^2 + 8^2}

\text {Radius = }\sqrt{100}

\text {Radius = }10

Area = π (10)² = 100π = 314 units²

6 0
3 years ago
The ratio of the number of student in mr. Moore’s class compared to the number of student in miss Henry’s class is 5:4. The rati
Ahat [919]

Answer:

10:9

Step-by-step explanation:

First ratio is 5:4. 4 is equal to Henry class

If you múltiply the ratio by 2 you get

10:8, This ratio can be compared because now Henry class has 8

2(5:4)

10:8

8:9

Meaning that the answer is 10:9

7 0
3 years ago
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