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ozzi
3 years ago
9

Multiply the following polynomials and enter the MISSING LINEAR Term :

Mathematics
2 answers:
lina2011 [118]3 years ago
8 0
- 15y4 - 33y3 + y2 + 8 = - 33y3 + 3y2
- 15y4 - 2y3 + 8
Inessa05 [86]3 years ago
6 0

We are given

-3y(5y^3+11y^2-y+8)=-15y^4-33y^3+3y^2-........?........

Firstly, we will simplify left side

and then we can compare it with right side

Left side:

-3y(5y^3+11y^2-y+8)

We can distribute -3y

=-3y*5y^3+-3y*11y^2--3y*y+-3y*8

now, we can simplify it

=-15y^4-33y^3+3y^2-24y

now, we can compare it with right side

we can see that only last term is missing

so, there should be -24y in last term

so, we get

-3y(5y^3+11y^2-y+8)=-15y^4-33y^3+3y^2-24y.................Answer

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2 Points
Inga [223]

Answer:

D

Step-by-step explanation:

Given

9 - 7x = (4x - 3)² + 5 ← expand the squared factor

9 - 7x = 16x² - 24x + 9 + 5, that is

9 - 7x = 16x² - 24x + 14 ( subtract 9 - 7x from both sides )

0 = 16x² - 17x + 5, that is

16x² - 17x + 5 = 0 ← in standard form → D

4 0
3 years ago
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DaniilM [7]

Answer:

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Step-by-step explanation:

The two perpendicular side lengths are equal, so using Pythagoras theorem:

x = sqrt( sqrt(10)^2 + sqrt(10)^2 )

x = sqrt(10 + 10)

x = sqrt(20)

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3 years ago
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sdas [7]

Answer:

7.71 is the answer hope you get it

3 0
3 years ago
I don't know how to do this
Dvinal [7]
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3 0
3 years ago
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Viktor [21]

Answer:

c.

Step-by-step explanation:

7 0
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