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Katyanochek1 [597]
4 years ago
6

Can someone tell me if this is correct or not

Mathematics
2 answers:
SCORPION-xisa [38]4 years ago
6 0
117 is the correct answer
natima [27]4 years ago
3 0

Answer:

I think it is correct

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(Anyone?) it’s easy just do it pls
telo118 [61]

Answer:

if it's easy why dont you do it,that picture dont even take good

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3 years ago
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3 times 9 times 10 to the first power
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3x9x10^1
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Simplify the expresion: 2+(a+8)
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A + 10 is the answer.
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3 years ago
Use the Divergence Theorem to evaluate the following integral S F · N dS and find the outward flux of F through the surface of t
Xelga [282]

Answer:

Result;

\int\limits\int\limits_S { \textbf{F}} \, \cdot \textbf{N} d {S} = 32\pi

Step-by-step explanation:

Where:

F(x, y, z) = 2(x·i +y·j +z·k) and

S: z = 0, z = 4 -x² - y²

For the solid region between the paraboloid

z = 4 - x² - y²

div F        

For S: z = 0, z = 4 -x² - y²

We have the equation of a parabola

To verify the result for F(x, y, z) = 2(x·i +y·j +z·k)

We have for the surface S₁ the outward normal is N₁ = -k and the outward normal for surface S₂ is N₂ given by

N_2 = \frac{2x \textbf{i} +2y \textbf{j} + \textbf{k}}{\sqrt{4x^2+4y^2+1} }

Solving we have;

\int\limits\int\limits_S { \textbf{F}} \, \cdot \textbf{N} d {S} = \int\limits\int\limits_{S1} { \textbf{F}} \, \cdot \textbf{N}_1 d {S} + \int\limits\int\limits_{S2} { \textbf{F}} \, \cdot \textbf{N}_2 d {S}

Plugging the values for N₁ and N₂, we have

= \int\limits\int\limits_{S1} { \textbf{F}} \, \cdot \textbf{(-k)}d {S} + \int\limits\int\limits_{S2} { \textbf{F}} \, \cdot  \frac{2x \textbf{i} +2y \textbf{j} + \textbf{k}}{\sqrt{4x^2+4y^2+1} } d {S}

Where:

F(x, y, z) = 2(xi +yj +zk) we have

= -\int\limits\int\limits_{S1} 2z \ dA + \int\limits\int\limits_{S2} 4x^2+4y^2+2z \ dA

= -\int\limits^2_{-2} \int\limits^{\sqrt{4-y^2}} _{-\sqrt{4-y^2}} 2z \ dA + \int\limits^2_{-2} \int\limits^{\sqrt{4-y^2}} _{-\sqrt{4-y^2}} 4x^2+4y^2+2z \ dA

= \int\limits^2_{-2} \int\limits^{\sqrt{4-y^2}} _{-\sqrt{4-y^2}} 4x^2+4y^2 \ dxdy

= \int\limits^2_{-2} \frac{(16y^2 +32)\sqrt{-(y^2-4)} }{3} dy

= 32π.

6 0
4 years ago
Julissa is running a 10-kilometer race at a constant pace. After running for 18 minutes, she completes 2 kilometers. After runni
trasher [3.6K]

For this case, the first thing we must do is define variables.

We have then:

t: the time in minutes

k: the number of kilometers

The relationship between both variables is direct.

Therefore, the function is:

k (t) = c * t

Where, "c" is a constant of proportionality.

To determine "c" we use the following data:

After running for 18 minutes, she completes 2 kilometers.

Substituting values:

2 = c * 18

Clearing c we have:

c = \frac{2}{18}

c = \frac{1}{9}

Then, the equation is given by:

k (t) = \frac{1}{9} * t

Answer:

An equation that can be used to represent k, the number of kilometers Julissa runs in t minutes is:

k (t) = \frac{1}{9} * t

7 0
4 years ago
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