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3 years ago

Find the common ratio of the sequence. –172, –86, –43, –21.5, . . .

Mathematics

2 answers:

ra1l [238]3 years ago

6 0

The common ratio of each one is 1/2 or .5
If ya need any more help let me know.
Brainliest?

seropon [69]3 years ago

4 0

If you divide each number by the previous one, you get:

-86 / -172 = 1/2
-43 / -86 = 1/2
-21.5 / -43 = 1/2

The common ratio is 1/2 = 0.5

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3 years ago

Calculate the flux of the vector field F⃗ (x,y,z)=(exy+9z+4)i⃗ +(exy+4z+9)j⃗ +(9z+exy)k⃗ through the square of side length 3 wit

ikadub [295]

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$(x\,\vec\imath+y\,\vec\jmath+z\,\vec k)\cdot(\vec\imath-\vec k)=0\implies x-z=0\implies z=x$

We can parameterize this surface by

$\vec s(x,y)=x\,\vec\imath+y\,\vec\jmath+x\,\vec k$

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$\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\iint_S\vec F(\vec s(x,y))\cdot\vec n\,\mathrm dx\,\mathrm dy$

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3 years ago

How to put y-3x=19 into intercept form

Musya8 [376]

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3 years ago

A technician charges P 400 per hour and spends P 500 a day on gasoline. Write an alcat expression to represent his earnings for

Basile [38]

Answer:

y=400*x-500

Step-by-step explanation:

The expression that represents the problem is:

y=400*x-500

Function y represents earnings for one day.

400 is the fixed number that is charge for one hour work

x represents the number of hours that the technician has worked for one day

To find the total earnings you should multiply the fixed charge for one hour work (400) by the number of hours worked in a day.

Then you need to substract the cost of gasoline in a day, it is 500 and it is a constant in the equation since it doesn't depend on the number of hours worked.

So, the function is:

y=400*x-500

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2 years ago