We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.
We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.
Formula for combination:
Where 
represents the number of objects/people in the set and 
represents the number of objects/people being chosen from the set
There are 23 people in the set and 10 people being chosen from the set
Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get
Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!
~ Padoru
I only know 1 & 4 .. 2 & 3 seem hard to me ..
X >7
X< -7
-
The answer is 170. First you add base one and base two divide by twi the multiply that by the height. 18+22=40 40/2=20 20•8.5=170
Answer:
5
Step-by-step explanation:
The interquartile range is the difference between the upper quartile and the lower quartile.
First find the median.
The median is the middle value of the data set arranged in ascending order
1 5 5 7 9 ← data in ascending order
↑ median
The lower quartile is the middle value of the data to the left of the median. If there is not an exact middle then it the average of the values on either side of the middle.
1 5
↑ lower quartile = 
= 3
The upper quartile is the middle value of the data to the right of the median.
7 9
↑ upper quartile = 
= 8
Thus
interquartile range = 8 - 3 = 5
Answer:
Step-by-step explanation:
EH=w
then it is as simple as pluggin in
gh=4(eh)-51
