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snow_tiger [21]
3 years ago
9

Simplify the expression (7a5b6)4 . Please help

Mathematics
2 answers:
IceJOKER [234]3 years ago
5 0

Answer:

28a20b24

Step-by-step explanation:

7(4)=28a

5(4)=20b

6(4)=24

so you put it all together which is: 28a20b24

8_murik_8 [283]3 years ago
3 0

Answer:

28a 20b 24

Step-by-step explanation:

You might be interested in
4/7 divided by 1 3/4
poizon [28]

Answer:

16/49

Step-by-step explanation:

4/7 ÷ 1 3/4

Convert 1 3/4 into an improper fraction

4/7 ÷ 7/4

Find the reciprocal of 7/4 and multiply

4/7 * 4/7

16/49

Hope this helps :)

7 0
3 years ago
Can u plz help meh with this 6th grade math. U have to write an algebraic equation and solve. Only solve 2, 3, 4, 7, 8. Thank Yo
ra1l [238]
2. 24-7p=10
-7p=-14
p=2

3. x+(x+1)+(x+2)=72
3x+3=72
3x=69
x=23

4. x+(x+2)+(x+4)=48
3x+6=48
3x=42
x=14

7. 40-2x=8
-2x=-32
x=16

8. 1/2x+4=12
1/2x=8
x=16
3 0
2 years ago
Please do this correct if inappropriate then report and no LINKS and also will do brainly
Nuetrik [128]
Mean=87.5
Median=88
Mode=79,85,86,90,92,93 so technically all the numbers show are the mode cause they all repeat 1 time but if there were two of the same number that would be the mode cause there’s two and not one so you always go by which one repeats more!
4 0
2 years ago
Deer ticks can be carriers of either Lyme disease or human granulocytic ehrlichiosis (HGE). Based on a recent study, suppose tha
san4es73 [151]

Answer:

0.2364

Step-by-step explanation:

We will take

Lyme = L

HGE = H

P(L) = 16% = 0.16

P(H) = 10% = 0.10

P(L ∩ H) = 0.10 x p(L U H)

Using the addition theorem

P(L U H) = p(L) + P(H) - P(L ∩ H)

P(L U H) = 0.16 + 0.10 - 0.10 * p(L u H)

P(L U H) = 0.26 - 0.10p(L u H)

We collect like terms

P(L U H) + 0.10P(L U H) = 0.26

This can be rewritten as:

P(L U H)[1 +0.1] = 0.26

Then we have,

1.1p(L U H) = 0.26

We divide through by 1.1

P(L U H) = 0.26/1.1

= 0.2364

Therefore

P(L ∩ H) = 0.10 x 0.2364

The probability of tick also carrying lyme disease

P(L|H) = p(L ∩ H)/P(H)

= 0.1x0.2364/0.1

= 0.2364

3 0
2 years ago
A veterinarian estimated the weight of a puppy to be 7 kg. The actual weight of the puppy was 6.6 kg.
KIM [24]

9514 1404 393

Answer:

  • absolute error: 0.4 kg
  • relative error: 6.1%

Step-by-step explanation:

The absolute error is the difference between the estimate and the actual weight:

  7.0 kg -6.6 kg = 0.4 kg . . . . absolute error

__

The relative error is the ratio of the absolute error to the actual weight:

  (0.4 kg)/(6.6 kg) × 100% = 6.060606...% ≈ 6.1% . . . . relative error

6 0
3 years ago
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