Answer:
(-∞, -2) and (2, ∞)
Step-by-step explanation:
ƒ(x) = x³ -12x + 10
f'(x) = 3x² - 12
Set 3x² - 12 = 0
x² - 4 = 0
x² = 4
x = ±2
The points x = -2 and x = + 2 divide the number line into three intervals:
(-∞, -2), (-2, +2), and (+2, ∞).
a. Interval (-∞, -2)
x < -2, so f'(x) > 0 when -∞ < x < -2
The function is increasing in (-∞, -2).
b. Interval (-2, 2)
|x| < 2, so f'(x) <0
The function is decreasing in (-2, 2).
c. Interval (2, ∞)
x > 2, so f'(x) > 0 when 2 < x < ∞
The function is increasing in (2, ∞).
Thus, the function is increasing in the intervals (-∞, -2) and (2, ∞).
Answer:
P=p1+p2+p3+p4
P1=4*a=4*8=24
P2=a+b+c=6+10+8=24
P3=2*a+2*b=2*10+2*20=60=P4
P=24+24+60+60=160cm
Hi there,
2 + 14x + 17 = -96
19 + 14x = -96
14x = -96 - 19
14x = -115
Hence, X = 8.21429
X = -115/14
X = -8 3/14
Hope this helps :)
Answer:I am pretty sure its 800
Step-by-step explanation: