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madreJ [45]
3 years ago
15

Provide two examples that show that all square roots are not irrational numbers ?

Mathematics
1 answer:
Flura [38]3 years ago
5 0

Answer:

\sqrt{4}, \ \sqrt{9} \text{ are rational numbers.}

Step-by-step explanation:

Hello,

\sqrt{n^2}=n \ for \ n\geq 0\\\\\text{For instance}\\\\\sqrt{2^2}=2=\sqrt{4}\\\\\sqrt{3^2}=3=\sqrt{9}

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The profit earned by a hot dog stand is a linear function of the number of hot dogs sold. It costs the owner $48 dollars each mo
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3 years ago
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Please...Solve the inequality, and then graph its solution: 5 + 2x - 2 < 12 + 8x - 3x​
andreev551 [17]

Rewrite so

x

is on the left side of the inequality.

12

+

8

x

−

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x

≥

5

+

2

x

−

2

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3

x

from

8

x

.

12

+

5

x

≥

5

+

2

x

−

2

Subtract

2

from

5

.

12

+

5

x

≥

2

x

+

3

Move all terms containing

x

to the left side of the inequality.

Tap for more steps...

12

+

3

x

≥

3

Move all terms not containing

x

to the right side of the inequality.

Tap for more steps...

3

x

≥

−

9

Divide each term by

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and simplify.

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x

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The result can be shown in multiple forms.

Inequality Form:

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≥

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Interval Notation:

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−

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∞

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3 0
2 years ago
I need help :p......​
IRISSAK [1]

Answer:

I believe the answer is C

Step-by-step explanation:

3 0
3 years ago
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