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3 years ago

In the diagram, PN is the perpendicular bisector of AB and is also the angle bisector of

1 answer:

7 0

The perpendicular bisector is a line segment that is drawn from a vertex of an angle to the midpoint of another line segment creating a right triangle or a 90° angle in the process. Suppose AB is the base segment of the triangle, therefore the perpendicular sector is also the angle bisector of the other angle of the triangle, supposedly angle C. Angle bisector is a line segment that divides the angle into two equal parts. Imagine a line drawn from the top vertex C extended down to the midpoint of line AB. That is the perpendicular and angle bisector.

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Ed deposited $6000 into a savings account 4 years ago. The simple interest rate is 3%. How much does Ed have in his account now?

Serga [27]

Answer:

$200,000

Step-by-step explanation:

6,000×100=600,000

600,000÷3=200,000

So $200,000

8 0

3 years ago

Read 2 more answers

1) (19, −16), (-7, -15) what is the slope of the line through each pair of points

antiseptic1488 [7]

The slope of the line which passes through (19,-16) and (-7,-15) is -1/26.

Given that the points through which the line passes is (19,-16) and (-7,-15).

We are required to find the slope of the line which passes through (19,-16) and (-7,-15).

The slope of a line is basically a measure of its steepness.It is basically the difference between y coordinate divided by the difference between x coordinate. We can form an equation with the help of the slope.

Points=(19,-16) and (-7,-15)

Slope=(-15+16)/(-7-19)

=1/-26

=-1/26

Hence the slope of the line which passes through (19,-16) and (-7,-15) is -1/26.

Learn more about slope at brainly.com/question/3493733

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5 0

2 years ago

Find x in the following diagram

andreyandreev [35.5K]

Answer:

x = 71

Step-by-step explanation:

The sum of the measures of the exterior angles of a polygon is always 360°.

A triangle has 3 exterior angles.

152+ 137+x = 360

Combine like terms

289 +x = 360

Subtract 289 from each side

289-289+x=360-289

x = 71

8 0

3 years ago

3(x+y)=y if (x y) is a solution to the equation above and y=0 what is the ratio x/y

Alona [7]

The equation can be rewritten as x = -2/3 y, so x/y = -2/3
However, for y=0, the ratio is undefined as you would be dividing by 0??

3 0

3 years ago

The coordinates of polygon ABCD are A(-4,-1), B(-2,3), C(2,2), and D(4,-3). Use these coordinates to complete the sentences belo

oee [108]

Answer:

The perimeter of polygon ABCD, to the nearest thousandth units is

22.227 units

The perimeter of polygon ABCD', to the nearest thousandth, would be 20.980 units

The area of polygon ABCD' is 19.5 units²

Step-by-step explanation:

The coordinates forming the polygon are

A (-4,-1), B(-2,3), C(2,2), and D(4,-3)

The perimeter then is given by the sum of the length of the sides as follows;

Length of line between two X and Y points distance, xi and yj apart is

length XY = $\sqrt{x^2+y^2}$

Therefore, the length between points AB is

length AB = $\sqrt{(-4 - (-2))^2+(-1-3)^2}$

= $\sqrt{(-4 +2)^2+(-4)^2} = \sqrt{-2^2+-4^2} = \sqrt{20}$ = 4.472 units

Similarly, length BC is given by

Length BC = $\sqrt{(-4)^2+1^2} = \sqrt{17}$ = 4.123 units

Length CD = $\sqrt{(-2)^2+5^2} = \sqrt{29}$ = 5.385 units

Length DA = $\sqrt{(8)^2+(-2)^2} = \sqrt{68}$ = 8.246 units

The perimeter is equal to;

length AB + Length BC + Length CD + Length DA

= 4.472 + 4.123 + 5.385 + 8.246 = 22.227 units

If the point D is moved up 2 units and left 1 unit we have

D' = x-1, y+2 where x and y are the coordinates of point D

D(4, -3) → D'((4-1), (-3+2)) = D'(3, -1)

The length D'A = $\sqrt{(7)^2+(0)^2} = \sqrt{49}$ =7 units

The perimeter of polygon ABCD'

length AB + Length BC + Length CD + Length D'A

= 4.472 + 4.123 + 5.385 + 7 = 20.980 units.

The area is given by the determinant of the 3 by 3 matrix using Cramer's Rule as follows

$S_{\bigtriangleup}$ = $(\frac{1}{2})|x_1y_2+x_2y_3+x_3y_1-x_1y_3-x_2y_1-x_3y_2|$

= $(\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|$

Triangle ABC we have

A(-4,-1)

B(-2,3)

C(2,2)

$S_{{\bigtriangleup}ABC}$ = $(\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|$

$=(\frac{1}{2})|(-4)(3-2)+(-2)(2-(-1)) +2((-1)-3)|$

= $=(\frac{1}{2})|-4-6 -8|= 9 units^2$

Triangle ACD'

A(-4,-1)

C(2,2)

D'(3, -1)

$S_{{\bigtriangleup}ACD'}$ = $(\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|$

$=(\frac{1}{2})|(-4)(2+1)+(2)(-1+1) +3((-1)-2)| = \frac{21}{2}$ = 10.5 units²

Area of polygon = $S_{{\bigtriangleup}ABCD'}$ = $S_{{\bigtriangleup}ABC}$ + $S_{{\bigtriangleup}ACD'}$ = (9 + 10.5) units²

Area of polygon ABCD' = 19.5 units².

7 0

3 years ago