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2 years ago

Find the product 0.037 · 0.26

Mathematics

2 answers:

Eva8 [605]2 years ago

7 0

0.00962

0.037 • 0.26 = 0.00962

Helga [31]2 years ago

5 0

0.00962

Explanation: .037 • .26 = 0.00962

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A bookkeeper bought 2,000 exercise book distributed 200 books to the student from poor economic background as donation .he sold

Andrews [41]

Books left=2000-200=1800

ATQ

$\\ \sf\longmapsto 1800x+10=0.08x$

$\\ \sf\longmapsto 1800x-0.08x=-10$

$\\ \sf\longmapsto x(1800-0.08)=-10$

$\\ \sf\longmapsto x(1799.92)=-10$

$\\ \sf\longmapsto x=|\dfrac{10}{1799.92}|$

$\\ \sf\longmapsto x=0.005$

Now

$\\ \sf\longmapsto CP=0.005(2000)=10$

6 0

2 years ago

What is the only unknown (variable) needed to find the volume of a sphere?

yuradex [85]

Sphere

The radius of the sphere is the only unknown variable need to find the volume of a sphere.

Step-by-step explanation:

Sphere is a geometrical three dimensional round figure with every point on its surface equidistant from its center. It is a three dimensional representation of a circle. A line which connects from the center to the surface is called radius of the sphere.The diameter of the sphere is the longest straight line which passes through the center of the sphere.

The volume of sphere is given by:

Volume of sphere(V) = $\frac{4}{3}\pi r^{3} \\$

where V is the volume of the sphere

r is the radius of the sphere

$\pi = \frac{22}{7}$ = 3.14

Hence the only unknown variable to find the volume of a sphere is the radius.

5 0

2 years ago

Suppose that W1, W2, and W3 are independent uniform random variables with the following distributions: Wi ~ Uni(0,10*i). What is

nadya68 [22]

I'll leave the computation via R to you. The $W_i$ are distributed uniformly on the intervals $[0,10i]$ , so that

$f_{W_i}(w)=\begin{cases}\dfrac1{10i}&\text{for }0\le w\le10i\\\\0&\text{otherwise}\end{cases}$

each with mean/expectation

$E[W_i]=\displaystyle\int_{-\infty}^\infty wf_{W_i}(w)\,\mathrm dw=\int_0^{10i}\frac w{10i}\,\mathrm dw=5i$

and variance

$\mathrm{Var}[W_i]=E[(W_i-E[W_i])^2]=E[{W_i}^2]-E[W_i]^2$

We have

$E[{W_i}^2]=\displaystyle\int_{-\infty}^\infty w^2f_{W_i}(w)\,\mathrm dw=\int_0^{10i}\frac{w^2}{10i}\,\mathrm dw=\frac{100i^2}3$

so that

$\mathrm{Var}[W_i]=\dfrac{25i^2}3$

Now,

$E[W_1+W_2+W_3]=E[W_1]+E[W_2]+E[W_3]=5+10+15=30$

and

$\mathrm{Var}[W_1+W_2+W_3]=E\left[\big((W_1+W_2+W_3)-E[W_1+W_2+W_3]\big)^2\right]$

$\mathrm{Var}[W_1+W_2+W_3]=E[(W_1+W_2+W_3)^2]-E[W_1+W_2+W_3]^2$

We have

$(W_1+W_2+W_3)^2={W_1}^2+{W_2}^2+{W_3}^2+2(W_1W_2+W_1W_3+W_2W_3)$

$E[(W_1+W_2+W_3)^2]$

$=E[{W_1}^2]+E[{W_2}^2]+E[{W_3}^2]+2(E[W_1]E[W_2]+E[W_1]E[W_3]+E[W_2]E[W_3])$

because $W_i$ and $W_j$ are independent when $i\neq j$ , and so

$E[(W_1+W_2+W_3)^2]=\dfrac{100}3+\dfrac{400}3+300+2(50+75+150)=\dfrac{3050}3$

giving a variance of

$\mathrm{Var}[W_1+W_2+W_3]=\dfrac{3050}3-30^2=\dfrac{350}3$

and so the standard deviation is $\sqrt{\dfrac{350}3}\approx\boxed{116.67}$

# # #

A faster way, assuming you know the variance of a linear combination of independent random variables, is to compute

$\mathrm{Var}[W_1+W_2+W_3]$

$=\mathrm{Var}[W_1]+\mathrm{Var}[W_2]+\mathrm{Var}[W_3]+2(\mathrm{Cov}[W_1,W_2]+\mathrm{Cov}[W_1,W_3]+\mathrm{Cov}[W_2,W_3])$

and since the $W_i$ are independent, each covariance is 0. Then

$\mathrm{Var}[W_1+W_2+W_3]=\mathrm{Var}[W_1]+\mathrm{Var}[W_2]+\mathrm{Var}[W_3]$

$\mathrm{Var}[W_1+W_2+W_3]=\dfrac{25}3+\dfrac{100}3+75=\dfrac{350}3$

and take the square root to get the standard deviation.

8 0

2 years ago

Determine the zero solution<br> f(x)=3x^(2)+5x-12

RideAnS [48]

Answer:

x= -3 or 4/3

Step-by-step explanation:

3x²+5x-12 =0

3x²+9x-4x-12=0

3x(x+3) -4(x+3) =0

(3x-4)(x+3)=0

x=-3 or 4/3

6 0

2 years ago

I need help in 10th grade math if you have any tips please help me

TiliK225 [7]

Answer:

I'll try to help you

..........

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2 years ago