The parent function is f(x) = ∛x
When you change the sign to get g(x) = - ∛x you are reflecting the function over the x-axis (because you are changing the sign of all the images).
When you do g(x + 8) to get h(x) = - ∛ (x + 8) you are shifting the functions 8 units to the left.
Therefore, the answer is the fourth option: reflect the parent function over the x-axis and translate it 8 units to the left.
Answer:
I believe it's 178.
Step-by-step explanation:
Answer:
Step-by-step explanation:
By the Isosceles Triangle Theorem, if 2 sides of a triangle are congruent to each other, than the angles opposite those sides are also congruent. We see by the markings on the triangle that WX and WY are congruent. That means that angle Y (which is across from WX) and angle X (which is across from WY) are the same measure. We can set them equal to each other because of this:
6y - 2 = 4x + 20
But we have a problem because we have 2 unknowns.
Let's try this out: the Triangle Angle-Sum Theorem says that all the angles of a triangle have to add together to equal 180. That means that
52 + 6y - 2 + 4x + 20 = 180.
But we STILL have a problem with those 2 unknowns. BUT...
If angle X and angle Y are the same, then we don't need both 6y - 2 AND 4x + 20. We only need 1 of those multiplied by 2 because they're the same measure. Changing things up a bit to reflect that:
52 + 2(4x + 20) = 180 and
52 + 8x + 40 = 180 and
8x = 88 so
x = 11.
That means that
4(11) + 20 = 64 which is the measure of both angles X and Y.
Let's check:
64 + 64 + 52 better equal 180. And it does, so we're good.
The value of x is found this way:
4x + 20 = 64 and
4x = 44 so
x = 11 which we already knew. Now for y:
6y - 2 = 64 and
6y = 66 and
y = 11 also.
Answer:
6
Step-by-step explanation:
The average rate of change over the interval ![[a,b]](https://tex.z-dn.net/?f=%5Ba%2Cb%5D)
for a function 
is 
.
So the average rate of change for 
on ![[2,4]](https://tex.z-dn.net/?f=%5B2%2C4%5D)
is:
.
Answer:
Geometric
Step-by-step explanation:
starting point : 800
800 , 1600 , 3200
Good luck .
