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2 years ago

Solve for h: v= πr ²h/3

Mathematics

1 answer:

wariber [46]2 years ago

6 0

V = πr²h/3
Multiply each side by 3.
3V = πr²h
Divide by πr².
3V/πr² = h

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Please help me with this math

fredd [130]

The part D is the correct one...

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2 years ago

Set A of six numbers has a standard deviation of 3 and set B of four numbers has a standard deviation of 5. Both sets of numbers

Alenkinab [10]

Given:

$\sigma_A=3$

$n_A=6$

$\sigma_B=5$

$n_B=4$

$\overline{x}_A=\overline{x}_B$

To find:

The variance. of combined set.

Solution:

Formula for variance is

$\sigma^2=\dfrac{\sum (x_i-\overline{x})^2}{n}$ ...(i)

Using (i), we get

$\sigma_A^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{n_A}$

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Similarly,

$\sigma_B^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{n_B}$

$(5)^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}$

$25=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}$

$100=\sum (x_i-\overline{x}_B)^2$

Now, after combining both sets, we get

$\sigma^2=\dfrac{\sum (x_i-\overline{x}_A)^2+\sum (x_i-\overline{x}_B)^2}{n_A+n_B}$

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2 years ago

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Answer:

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Step-by-step explanation:

Solving each of the inequalities

x + 3 ≥ 1 ( subtract 3 from both sides )

x ≥ - 2

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x ≥ $\frac{1}{3}$

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x ≥ 4 ← required solution

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The number of visits to public libraries increased from 1.5 billion in 1991 to 1.7 billion in 1996. Find the average rate of cha

nexus9112 [7]

The average rate of change between 1991 and 1996 is 40 million

<h3>How to determine the average rate of change between 1991 and 1996?</h3>

The given parameters are:

Population in 1991 = 1.5 billion

Population in 1996 = 1.7 billion

The average rate of change between 1991 and 1996 is calculated as:

Rate = (1.7 billion -1.5 billion)/(1996 - 1991)

Evaluate

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Hence, the average rate of change between 1991 and 1996 is 40 million

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brainly.com/question/8728504

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1 year ago