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2 years ago

14

Does this table represent a function? Why or why not?

1 answer:

sleet_krkn [62]2 years ago

6 0

Answer:

not function because the x repeats and for it to be a function the x can not repeat for example the 2 is repeating in the table

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Multiple Choice: What method can be used to prove the triangles below are congruent? * Angle Side Angle (ASA) Angle Angle Side (

Aneli [31]

Answer:

angle side angle

Step-by-step explanation:

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2 years ago

Line AB has a length of 5 cm. The line segment is dilated to produce line A'B', which has a length of 2 cm. Find the scale facto

nasty-shy [4]

<span>The correct answer is A. k = 2/5</span>

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3 years ago

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Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III

vodka [1.7K]

Given:

$\sin x=-\dfrac{15}{17}$

x lies in the III quadrant.

To find:

The values of $\sin 2x, \cos 2x, \tan 2x$ .

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.

We know that,

$\sin^2 x+\cos^2 x=1$

$(-\dfrac{15}{17})^2+\cos^2 x=1$

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x lies in the III quadrant. So,

$\cos x=-\sqrt{\dfrac{64}{289}}$

$\cos x=-\dfrac{8}{17}$

Now,

$\sin 2x=2\sin x\cos x$

$\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})$

$\sin 2x=-\dfrac{240}{289}$

And,

$\cos 2x=1-2\sin^2x$

$\cos 2x=1-2(-\dfrac{15}{17})^2$

$\cos 2x=1-2(\dfrac{225}{289})$

$\cos 2x=\dfrac{289-450}{289}$

$\cos 2x=-\dfrac{161}{289}$

We know that,

$\tan 2x=\dfrac{\sin 2x}{\cos 2x}$

$\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}$

$\tan 2x=\dfrac{240}{161}$

Therefore, the required values are $\sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}$ .

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2 years ago

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levacccp [35]

Answer:

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Step-by-step explanation:

So when we multiply this is what we get:

$\frac{x-5}{4}=13$

then we multiply the 4 by 13:

$x-5=52$

then after that we add 52+5 and we get:

$x=57\\$

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1 year ago

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I don't know what you have to do but I'm trying to do my first answer srry

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1 year ago

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