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3 years ago

Six times a number increased by 9

Mathematics

2 answers:

Gala2k [10]3 years ago

7 0

6x+9 is the answer to the question

yulyashka [42]3 years ago

5 0

6x+9 is the answer to the question

the other answer 3x-7

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A copy machine makes 36 copies per minute. How long does it take to make 117 copies

tensa zangetsu [6.8K]

Answer:

3.25 minutes

Step-by-step explanation:

117 ÷ 36 = 117

4 0

3 years ago

Read 2 more answers

Which of the following sets are subspaces of R3 ?

Ratling [72]

Answer:

The following are the solution to the given points:

Step-by-step explanation:

for point A:

$\to A={(x,y,z)|3x+8y-5z=2} \\\\\to for(x_1, y_1, z_1),(x_2, y_2, z_2) \varepsilon A\\\\ a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)$

$=3(aX_l +bX_2) + 8(ay_1 + by_2) — 5(az_1+bz_2)\\\\=a(3X_l+8y_1- 5z_1)+b (3X_2+8y_2—5z_2)\\\\=2(a+b)$

The set A is not part of the subspace $R^3$

for point B:

$\to B={(x,y,z)|-4x-9y+7z=0}\\\\\to for(x_1,y_1,z_1),(x_2, y_2, z_2) \varepsilon B \\\\\to a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)$

$=-4(aX_l +bX_2) -9(ay_1 + by_2) +7(az_1+bz_2)\\\\=a(-4X_l-9y_1+7z_1)+b (-4X_2-9y_2+7z_2)\\\\=0$

$\to a(x_1,y_1,z_1)+b(x_2, y_2, z_2) \varepsilon B$

The set B is part of the subspace $R^3$

for point C: $\to C={(x,y,z)|x$

In this, the scalar multiplication can't behold

$\to for (-2,-1,2) \varepsilon C$

$\to -1(-2,-1,2)= (2,1,-1)$ ∉ C

this inequality is not hold

The set C is not a part of the subspace $R^3$

for point D:

$\to D={(-4,y,z)|\ y,\ z \ arbitrary \ numbers)$

The scalar multiplication s is not to hold

$\to for (-4, 1,2)\varepsilon D\\\\\to -1(-4,1,2) = (4,-1,-2)$ ∉ D

this is an inequality, which is not hold

The set D is not part of the subspace $R^3$

For point E:

$\to E= {(x,0,0)}|x \ is \ arbitrary) \\\\\to for (x_1,0 ,0) ,(x_{2},0 ,0) \varepsilon E \\\\\to a(x_1,0,0) +b(x_{2},0,0)= (ax_1+bx_2,0,0)\\$

The $x_1, x_2$ is the arbitrary, in which $ax_1+bx_2$ is arbitrary

$\to a(x_1,0,0)+b(x_2,0,0) \varepsilon E$

The set E is the part of the subspace $R^3$

For point F:

$\to F= {(-2x,-3x,-8x)}|x \ is \ arbitrary) \\\\\to for (-2x_1,-3x_1,-8x_1),(-2x_2,-3x_2,-8x_2)\varepsilon F \\\\\to a(-2x_1,-3x_1,-8x_1) +b(-2x_1,-3x_1,-8x_1)= (-2(ax_1+bx_2),-3(ax_1+bx_2),-8(ax_1+bx_2))$

The $x_1, x_2$ arbitrary so, they have $ax_1+bx_2$ as the arbitrary $\to a(-2x_1,-3x_1,-8x_1)+b(-2x_2,-3x_2,-8x_2) \varepsilon F$

The set F is the subspace of $R^3$

5 0

3 years ago

Six friends went out to lunch they each started with the same amount of money and they each spent 8$ they ended with a combined

ss7ja [257]

Answer:

Step-by-step explanation:

4 0

3 years ago

Please help 20 points and brainliest

Zanzabum

Answer:

Step-by-step explanation:

a.) Graph the points onto the graph according to the table i created.

b.) 2x + y = -3

+2x +2x

y = 2x - 3

She is incorrect. The correct linear equation is y = -2x - 3

3 0

3 years ago

Find the equation of the line using the point-slope formula. Write all the final equations

vivado [14]

Answer:

$y=\frac{1}{2}x+\frac{5}{2}$

Step-by-step explanation:

We are going to find the slope by lining up the points vertically and subtract, then put 2nd difference over first.

Also you could just use $\frac{y_2-y_1}{x_2-x_1}$ . It is the same thing.

( 5 , 5)

-( 1 , 3)

--------------

4 2

So the slope is 2/4 or 1/2 after reducing.

The point-slope form a line is

$y-y_1=m(x-x_1)$ with a point on the line $(x_1,y_1)=(1,3)$ given and with slope $m=\frac{1}{2}$ given.

$y-3=\frac{1}{2}(x-1)$

We are going to solve this for y and simplify what we can because our goal is y=mx+b; this is slope-intercept form. It is called that because it tells us the slope,m, and the y-intercept,b.

Distribute:

$y-3=\frac{1}{2}x-\frac{1}{2}$

Add 3 on both sides:

$y=\frac{1}{2}x-\frac{1}{2}+3$

Simplify:

$y=\frac{1}{2}x+\frac{5}{2}$

4 0

3 years ago