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Step2247 [10]
2 years ago
6

What the answer to this ?

Mathematics
1 answer:
Zina [86]2 years ago
5 0

Answer:

B.16

Step-by-step explanation:

let the 4 consecutive numbers be x, x+1, x+2 and x+3

x+x+1+x+2+x+3=58

4x+6=58

4x=58-6

4x=52

4x/4=52/4

x=13

the largest number is x+3 so

x+3=13+3=<u>16</u>

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Jack, Jill, and Ron share a 2-bedroom apartment. Rent is represented by R. The water bill is $20 per person. The electric bill i
erastovalidia [21]
Jack: 2R/3
Jill: 3 • 20 + 0.5 • 250 = 185
Ron: R/3 + 125

hope that helps

4 0
3 years ago
Find the sum of deviation of all observations of the data 5, 8, 10, 15, 22 from their mean.​
ivann1987 [24]

Answer:

the sum of deviation of all observations of the data 5, 8, 10, 15, 22 from their mean. =26

Step-by-step explanation:

Mean=sum of observation/ No. of observation

={5+8+ 10+ 15 + 22}/5

=60/5=12

Sum of deviations

= |5- 12| + |8 – 12| + |10- 12| + |15- 12| + |22-12|

= 7+4+2+ 3+ 10

= 26

3 0
2 years ago
F(x) = 2x + 3g(x) = 2x² + 6x + 13Find: (gºf)(x)
Butoxors [25]

Answer:

The function (gof)(x) is;

(g\circ f)(x)=8x^2+36x+49

Explanation:

Given the functions;

\begin{gathered} f(x)=2x+3 \\ g(x)=2x^2+6x+13 \end{gathered}

Solving for the function;

(g\circ f)(x)=g(f(x))

so, we have;

\begin{gathered} g(f(x))=2(f(x))^2+6(f(x))+13 \\ g(f(x))=2(2x+3)^2+6(2x+3)+13 \\ g(f(x))=2(4x^2+12x+9)^{}+6(2x)+6(3)+13 \\ g(f(x))=8x^2+24x+18^{}+12x+18+13 \\ g(f(x))=8x^2+24x^{}+12x+18+18+13 \\ g(f(x))=8x^2+36x+49 \end{gathered}

Therefore, the function (gof)(x) is;

(g\circ f)(x)=8x^2+36x+49

5 0
9 months ago
Louis bought a giant sub sandwich for the party. He wants to cut into 6-inch sections. If the sandwich is 18.25 feet, how many s
Lynna [10]
36.5
He’d have 36, 6 in sandwiches and a 3 inch section left
Explanation:
Take 18.25 and multiply by 12 which gives you 219. The amount of inches in the sandwich. Then divide 219 by 6 and you get 36.5
5 0
1 year ago
Please help on this!!
dexar [7]
3^8=6,561
6,561 •3=19,683

The highest altitude of an altocumulus cloud is 19,683 feet.
8 0
3 years ago
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