Answer: 
Step-by-step explanation:
Given
Two forces of 9 and 13 lbs acts
angle to each other
The resultant of the two forces is given by

Insert the values

Resultant makes an angle of

So, the resultant makes an angle of
with 9 lb force
Angle made with 13 lb force is 
Answer:
Step-by-step explanation:
11x+3y=103 and y=3x+1.
11x+3(3x+1)=103 -----> plug in (3x+1) for y in the first equation. You will want to distribute the 3 to the 3x+1 to get something that looks like:
11x+9x+3=103 ------> now you want to combine like terms
20x+3=103 ---> subtract 3 from both sides
20x=100 ----> divide both sides by 20
x=5
y=3(5)+1 ---> I like to plug in this to the equation that already has y isolated. 3*5 is 15, add 1 and you find that y=16.
(5, 16) will be your final answer (: