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3 years ago

G(x) = 5x h(x) = - 11x ^ 3 + 10x ^ 2 - 2x + 5

Mathematics

1 answer:

masya89 [10]3 years ago

8 0

Answer:

x(9x – 10).

Step-by-step explanation:

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How would i draw the line y= -x

kykrilka [37]

Answer:

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Step-by-step explanation:

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2 years ago

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Shakespeare wrote: All the world's a stage,/ And all the men and women merely players;/ They have their exits and their entrance

Bingel [31]

Answer:

Step-by-step explanation:

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2 years ago

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Evaluate the expression 100 - 9(d + 6) for d = 2. *

alexdok [17]

100-9(2+6)=100-9(8)=100-72=
so the answer is 28

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3 years ago

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What is the volume of a shipping cube with dimensions of 2 and 1/2 feet

Fantom [35]

For this case we have that by definition, the volume of a cube is given by:

$V = l ^ 3$

Where:

l: It's the side of the cube

According to the statement data:

$l = 2 \frac {1} {2} = \frac {2 * 2 + 1} {2} = \frac {5} {2}$

Substituting in the formula we have:

$V = (\frac {5} {2}) ^ 3\\V = \frac {5 ^ 3} {2 ^ 3}\\V = \frac {125} {8}\\V = 15.625$

Thus, the shipping cube volume is $15.625 \ ft ^ 3$

Answer:

$15.625 \ ft ^ 3$

6 0

3 years ago

This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an

sleet_krkn [62]

Answer:

-6re−r [sin(6θ) - cos(6θ)]

Step-by-step explanation:

the Jacobian is ∂(x, y) /∂(r, θ) = δx/δθ × δy/δr - δx/δr × δy/δθ

x = e−r sin(6θ), y = er cos(6θ)

δx/δθ = -6rcos(6θ)e−r sin(6θ), δx/δr = -sin(6θ)e−r sin(6θ)

δy/δθ = -6rsin(6θ)er cos(6θ), δy/δr = cos(6θ)er cos(6θ)

∂(x, y) /∂(r, θ) = δx/δθ × δy/δr - δx/δr × δy/δθ

= -6rcos(6θ)e−r sin(6θ) × cos(6θ)er cos(6θ) - [-sin(6θ)e−r sin(6θ) × -6rsin(6θ)er cos(6θ)]

= -6rcos²(6θ)e−r (sin(6θ) - cos(6θ)) - 6rsin²(6θ)e−r (sin(6θ) - cos(6θ))

= -6re−r (sin(6θ) - cos(6θ)) [cos²(6θ) + sin²(6θ)]

= -6re−r [sin(6θ) - cos(6θ)] since [cos²(6θ) + sin²(6θ)] = 1

6 0

3 years ago