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4 years ago

Which graph represents the function?

Mathematics

1 answer:

nignag [31]4 years ago

5 0

The domain cannot be 0, because then the bottom is 0
So domain is (-∞, 0) U (0, <span>∞)
That rules out B
The range cannot be 0, so the answer is C

The second one is A</span>

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The converse of a conditional statement is "If the sum of the exterior angles of a figure is 360°, then the figure is a polygon.

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4 years ago

Read 2 more answers

What is the diameter of a circle if its circumference is 12 feet?

ryzh [129]

Answer:

Explanation:

Circumference ÷ π = Diameter

12 ÷ 3.14 = Diameter

12 ÷ 3.14 = 3.82165605096

3.82165605096 Ft. Is The Diameter

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3 years ago

PROBLEM: (IF YOU TROLL I WILL REPORT) Riley has a rectangular shaped patio that is 13 feet long by 15 feet wide. He wants to DOU

rusak2 [61]

Answer:

Part A)

$390=(15+x)(13+x)$

Part B)

Approximately 18.77 feet long by 20.77 feet wide.

Step-by-step explanation:

Currently, the patio is 13 feet long by 15 feet wide. Therefore, the area right now is:

$A=13(15)=195\text{ feet}^2$

We will increase the length and width of the patio by the same amount such that the new area is double the previous amount.

Part 1)

The previous area is 195. Therefore, we would like to the new area to be twice of that. Hence, the new area is:

$A=2(195)=390$

We will increase the length and the width by the same amount. Let’s call this amount x. Then by the area formula (A=bh), we can write:

$390=(15+x)(13+x)$

390 represents the doubled area. (15+x) is the width after the increase x, and (13+x) is the length after the same x increment.

Part 2)

So, we will solve for x. First, expand:

$390=195+15x+13x+x^2$

Simplify:

$x^2+28x+195=390$

Subtract 390 from both sides:

$x^2+28x-195=0$

This is a quadratic. Hence, we can use the quadratic formula:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Our a=1, b=28, and c=-195. Hence:

$x=\frac{-28\pm\sqrt{(28)^2-4(1)(-195)}}{2(1)}$

Evaluate:

$x=\frac{-28\pm\sqrt{1564}}{2}$

Simplify the square root:

$\sqrt{1564}=\sqrt{4}\cdot\sqrt{391}=2\sqrt{391}$

Hence:

$x=\frac{-28\pm2\sqrt{391}}{2}\\$

Simplify:

$x=-14+\sqrt{391} \text{ or } -14-\sqrt{391}$

Approximate:

$x\approx5.77\text{ or } x\approx-33.77$

In this case, we can reject the negative solution.

Hence, the value of x is 5.77.

This means that we should increase the our length and width by 5.77.

Hence, the new length will be 13+5.77 or about 18.77.

And our new width will be 15+5.77 or about 20.77.

So, the new dimensions is approximately 18.77 by 20.77

5 0

3 years ago

10.

aliina [53]

Answer:

B. If an object is dropped from a height of 38 feet, the function h(t) = –16t2 + 38 gives the height of the object after t seconds.

Step-by-step explanation:

The equation that models the movement of the object is:

Where,

t: time

a: acceleration due to gravity

v0: initial speed

h0: initial height

Suppose that the object falls with zero initial velocity and from a height of 38 feet.

The equation that models the problem is:

Answer:

If an object is dropped from a height of 38 feet, the function h (t) = -16t2 + 38 gives the height of the object after seconds

Answer: If an object is dropped from a height of 38 feet, the function h (t) = -16t2 + 38 gives the height of the object after seconds

Step-by-step explanation:

6 0

3 years ago