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horsena [70]
3 years ago
13

A field trip is planned which is 10 2/9 miles from school. A wheel of the school bus is punctured after 5 3/7. How many miles ar

e left to the field trip location?
Mathematics
1 answer:
lisabon 2012 [21]3 years ago
6 0
4 50/63 is the answer

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What would be the u to usub and what would be the steps to solving this integral?
shutvik [7]

Presumably, ln⁵(<em>x</em>) is the same as (ln(<em>x</em>))⁵ (as opposed to a quintuply-nested logarithm, log(log(log(log(log(<em>x</em>)))))).

Then substituting <em>u</em> = ln(<em>x</em>) and d<em>u</em> = d<em>x</em>/<em>x</em> gives

\displaystyle\int\frac{\mathrm dx}{x\ln^5(x)} = \int\frac{\mathrm du}{u^5} = -\frac1{4u^4}+C = \boxed{-\frac1{4\ln^4(x)}+C}

3 0
3 years ago
The graphs below have the same shape. What is the equation of the blue<br> graph?
Triss [41]
The blue graph is translated 3 units to the left and two down, so the new equation would be g(x)=(x-3)^2-2
5 0
3 years ago
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Explain your answer !! <br> Have a nice day
geniusboy [140]

1. keep the same

2. y=3/2y-13

5 0
3 years ago
.Find the vertex, zero(s), and y-intercept of the graph of y = x2 + 4x – 5.
scZoUnD [109]

Answer:

Vertex (-2,-9)

zeros: x=1, x=-5

y-intercept: -5

Step-by-step explanation:

When you graph the quadratic equation you obtain the parabola shown in the figure attached.

Find the vertex of the parabola observing the graph, you can that the minimum point of the parabola is at (-2,-9) this is the vertex.

The zeros are the x-intercepts:

x=1; x=-5

And the y-intecept is when x=0 and the parabola cut the y-axis. This is: -5.

8 0
3 years ago
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Factor the polynomial 8k^2 +80k +200
blondinia [14]
<h3>Solution:</h3>

8 {k}^{2}  + 80k + 200 \\  = 8( {k}^{2}  + 10k + 25) \\  = 8  [{k}^{2}  + 2(k)(5) +  ({5})^{2} ] \\  = 8( k + 5) ^{2}

<h3>Answer:</h3>

8( k + 5) ^{2}

<h3>Hope it helps..</h3>

ray4918 here to help

6 0
2 years ago
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