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Shtirlitz [24]
3 years ago
6

Which fraction equals a repeating decimal? a.5/80 b.11/88 c.17/85 d. 18/81

Mathematics
1 answer:
Marrrta [24]3 years ago
3 0
18/81 is 0.2 recurring
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Can you help me___________________________________
ludmilkaskok [199]
First problem: I believe YW: 34
ZX: 17
VX: 34. I have a pic attached but it probably doesn’t make much sense :)

7 0
3 years ago
What is the answer to this and can you explain
katovenus [111]

Answer:30

Step-by-step explanation:

5 0
3 years ago
HELP! PLZ I NEED THIS ASAP
harina [27]

Answer:

2x^{4}+x^{3}-x+2

Step-by-step explanation:

To find which one is prime, let's try to factor them all. We can use the factoring by grouping method.

x^{3}+3x^{2}-2x-6

x^{3}+3x^{2}and-2x-6

x^{2}(x+3)and-2(x+3)

So this one is not prime, since you can still factor it.

x^{3}+2x^{2}-3x-6

x^{3}+2x^{2}and-3x-6

x^{2}(x-2)and3(x-2)

So this one is not prime, since you can still factor it.

4x^{4}+4x^{2}-2x-2

4x^{4}+4x^{2}and-2x-2

4x^{3}(x+1)and-2(x+1)

So this one is not prime, since you can still factor it.

2x^{4}+x^{3}-x+2

2x^{4}+x^{3}and-x+2

x^{3}(2x+1)and -x+2 cannot be further factored.

Therefore, 2x^{4}+x^{3}-x+2 is a prime.

6 0
3 years ago
You created a scale drawing with the scale 1:8. The client asked you to change it to a scale of 1:10. Will your revised drawing
myrzilka [38]

Answer:

The revised drawing be larger or smaller than your original one

Step-by-step explanation:

The revised drawing be larger or smaller than your original one.

Because   a drawing at a scale of:

  • 1:10 means that the object is 10 times smaller than in real life scale 1:1
  • 1: 8 means that the object is 8 times smaller than in real life scale 1:1

So it means the revised drawing be larger or smaller than your original one

5 0
3 years ago
Read 2 more answers
Helppppppppppppppppppppppppppppppp
mel-nik [20]
Answer:
Third choice is the correct one

Explanation:
No fraction can have a denominator = 0 because this would make it undefined.
Therefore, the solution would be all the real values except for those that make the denominator = 0
Let's check the terms in the denominator:
i. c-3 = 0 at c = 3
ii. c = 0
iii. c(c-3) = 0 at c = 0 or c = 3
Therefore 0 and 3 are the values that would make the denominator zero.

Based on the above, the solution is all real numbers except 0 and 3

Hope this helps :)
3 0
3 years ago
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