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yanalaym [24]
3 years ago
14

Add. (5y - 1) + (-2y + 4) A) 3y - 5 B) 3y + 3 C) 7y + 3 D) 7y - 3

Mathematics
1 answer:
Ivan3 years ago
8 0
(5y - 1) + (-2y + 4)  = 5y - 1 - 2y + 4
                              = 5y - 2y - 1 + 4
                              = 3y + 3    [OPTION B] 
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I give you a tricky one Express 108 ×125as a product of prime factors in exponential form
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Answer:

108 \times 125=2^2 \times 3^3 \times 5^3

Step-by-step explanation:

To express the given product (108 X 125) as a product of prime factors

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Step 2: Write the product together, and combine any like terms if any

Therefore,

108 \times 125=2^2 \times 3^3 \times 5^3

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2 years ago
Factor completely: 2x4 − 32.
vazorg [7]

Answer:

Option b) is correct.

The completed factor of given expression is  2(x-2)(x+2)(x^2+4)

Step-by-step explanation:

Given expression is 2x^4-32

To find the completed factor for the given expression:

2x^4-32:

Taking the common number "2" outside  to the above expression we get

2x^4-32=2(x^4-16)

Now rewritting the above  expression as below

=2(x^4-2^4)  (since 16 can be written as the number 2 to the power of 4)

=2((x^2)^2-(2^2)^2)

The above expression is of the form a^2-b^2=(a+b)(a-b)

Here a=x^2 and  b=2^2

Therefore it becomes

=2(x^2+2^2)(x^2-2^2)

=2(x^2+4)(x^2-2^2)  

The above expression is of the form a^2-b^2=(a+b)(a-b)

Here a=x and  b=2

Therefore it becomes

=2(x^2+4)(x+2)(x-2)  

=2(x+2)(x-2)(x^2+4)  

Therefore =2(x+2)(x-2)(x^2+4)  

2x^4-32=2(x-2)(x+2)(x^2+4)  

Option b) is correct.

The completed factor of given expression is  2(x-2)(x+2)(x^2+4)

3 0
3 years ago
Read 2 more answers
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