All categories

2 years ago

How do I solve this what dose this mean.

Mathematics

1 answer:

lapo4ka [179]2 years ago

8 0

I think that Jasmine is right because she makes more sense to me

You might be interested in

20 POINTS PLS HELP ASAP

Cloud [144]

Answer:

Lot C

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Justin cuts a 10-inch-long roll of cookie dough into 6 equal-length pieces. How many inches long is each piece of cookie dough?

mixas84 [53]

Answer: Each piece is 1 2/3 inch length.

Step-by-step explanation:

Total length of cookie dough =10-inch

Since it is being into divided into 6 equal-length pieces

We have that each piece will have=1 0-inch / 6 = 5/3 = 1 2/3 inch length.

6 0

2 years ago

Why was the harlem renaissance in harlem?

Whitepunk [10]

Answer:

The great migration drew to Harlem some of the greatest minds and brightest talents of the day. some 300, 000 African Americans from the South had moved North.

Step-by-step explanation:

If this is not useful look up Harlem Renaissance website for information

6 0

2 years ago

It cost $109 per night to rent a motel room in Hampton. There is a one time $30 nonrefundable deposit required how much will it

bekas [8.4K]

Answer:

793

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

. Evaluate tan(α + β) = sin(????+????) / cos(????+????) to show tan(???? + ????) = tan(????)+tan(????????) / 1−tan(????) tan(???

grandymaker [24]

Answer with Step-by-step explanation:

We are given that

$tan(\alpha+\beta)$

$\frac{sin(\alpha+\beta}{cos(\alpha+\beta)}$

By using formula $tan x=\frac{sin x}{cos x}$

$\frac{sin\alpha cos\beta+sin\beta cos\alpha}{cos\alpha cos\beta-sin\alpha sin\beta}$

By using property: $sin(x+y)=sin x cosy+cos x sin y$

$cos(x+y)=cos x cosy-sin x siny$

Divide numerator and denominator by $cos\alpha cos\beta$

Then, we get

$\frac{\frac{sin\alpha}{cos\alpha}+\frac{sin\beta}{cos\beta}}{1-\frac{sin\alpha sin\beta}{cos\alpha cos\beta}}$

$tan(\alpha+\beta)=\frac{tan\alpha+tan\beta}{1-tan\alpha tan\beta}$

Hence, proved

Substitute $\alpha=\beta$

Then we get

$tan 2\alpha=\frac{tan\alpha+tan\alpha}{1-tan^2\alpha}$

$tan(2\alpha)=\frac{2tan\alpha}{1-tan^2\alpha}$

Hence, proved.

3 0

3 years ago