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3 years ago

10

Explain also please

1 answer:

liraira [26]3 years ago

5 0

J, (8,-3) because since they are diagonals, you can take the x and y values between the vertices and point of intersection.

For x
The distance between 2 and -4 is 6. Moving 6 in the other direction results in an x value of 8 (2+6)

For y
The distance between 5 and 1 is 4. Moving 4 in the other direction gives you a y value of -3 (1-4)

The answer is therefore (8,-3)

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Aleks [24]

Treating the data as a Venn set, it is found that:

26 students are good in mathematics only.

28 students are not good in any of the three courses.

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I am going to say that:

A is the number of students good in Math.
B is the number of students good in English.
C is the number of students good in Psychology.

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9 are good in all of the three courses.

This means that: $A \cap B \cap C = 9$

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13 are good in both mathematics and psychology

This means that:

$(A \cap C) + (A \cap B \cap C) = 13$

$(A \cap C) + 9 = 13$

$(A \cap C) = 4$

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15 are good in both mathematics and in English

This means that:

$(A \cap B) + (A \cap B \cap C) = 15$

$(A \cap B) + 9 = 15$

$(A \cap B) = 6$

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16 are good in both English and psychology

This means that:

$(B \cap C) + (A \cap B \cap C) = 16$

$(B \cap C) + 9 = 16$

$(B \cap C) = 7$

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20 are good in psychology

This means that:

$c + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 20$

$c + 4 + 7 + 9 = 20$

$c = 0$

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45 are good in mathematics

This means that:

$a + (A \cap B) + (A \cap C) + (A \cap B \cap C) = 45$

$a + 6 + 4 + 9 = 45$

$a = 26$

---------------------------------

Question a:

$a = 26$ , which means that 26 students are good in mathematics only.

---------------------------------

Question b:

At least one is:

$a + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 26 + 6 + 4 + 7 + 9 = 52$

Thus, 80 - 52 = 28

28 students are not good in any of the three courses.

A similar problem is given at: brainly.com/question/22003843

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Answer:

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Step-by-step explanation:

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