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4 years ago

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write an equation in point-slope form of the line having the given slope that contains the given point. m=−0.8, (14.5,12.8) sele

ct one: a. y−14.5=−0.8(x−12.8) b. y−12.8=−0.8(x−14.5) c. y=−0.8x−1.2 d. y 12.8=−0.8(x−14.5)

2 answers:

NARA [144]4 years ago

7 0

Y - y₁ = m(x -x₁)

slope m = -0.8, from point (14.5, 12.8) , x₁ = 14.5, y₁ = 12.8

y - y₁ = m(x -x<span>₁)

</span>y - 12.8 = -0.8(x - 14.5<span>)
</span>
<span>Option B </span>

Ganezh [65]4 years ago

4 0

Answer: b. $(y-12.8)=-0.8(x-14.5)$

Step-by-step explanation:

We know that the equation of a line in point slope form with slope m and passing through point (a,b) is given by :-

$(y-b)=m(x-a)$

Given : The slope of the line : m= -0.8

The point from which line is passing : (a,b) =(14.5,12.8)

Then , the equation in point slope form of the line having the given slope that contains the given point. m=−0.8, (14.5,12.8) :-

$(y-12.8)=-0.8(x-14.5)$

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Answer:

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Solving for n we got:

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And replacing the info we have:

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Step-by-step explanation:

Part a

For this case we have the following data given

$\bar X = 78.25$ represent the sample mean for the customer order totals

$\sigma =22.50$ represent the population deviation

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The confidence level is 90% or 0.90 and the significance level would be $\alpha=0.1$ and $\alpha/2 = 0.05$ and the critical value from the normal standard distirbution would be given by:

$z_{\alpha/2}=1.64$

And the confidence interval is given by:

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And replacing we got:

$78.25- 1.64 \frac{22.50}{\sqrt{40}}= 72.416$

$78.25+ 1.64 \frac{22.50}{\sqrt{40}}= 84.084$

Part b

The sample size is now n = 75, but the same confidence so the new interval would be:

$78.25- 1.64 \frac{22.50}{\sqrt{75}}= 73.989$

$78.25+ 1.64 \frac{22.50}{\sqrt{75}}= 82.511$

Part c

For this case when we increase the sample size the margin of error would be lower and then the interval would be narrower

Part d

The margin of error is given by:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

Solving for n we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

And replacing the info we have:

$n=(\frac{1.640(22.50)}{5})^2 =54.46 \approx 55$

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