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RoseWind [281]
3 years ago
11

write an equation in point-slope form of the line having the given slope that contains the given point. m=−0.8, (14.5,12.8) sele

ct one: a. y−14.5=−0.8(x−12.8) b. y−12.8=−0.8(x−14.5) c. y=−0.8x−1.2 d. y 12.8=−0.8(x−14.5)
Mathematics
2 answers:
NARA [144]3 years ago
7 0
Y - y₁ = m(x -x₁)

slope m = -0.8,  from point (14.5, 12.8) ,  x₁ = 14.5, y₁ = 12.8

 y - y₁ = m(x -x<span>₁)

</span>y - 12.8 = -0.8(x - 14.5<span>)
</span>
<span>Option B </span>
Ganezh [65]3 years ago
4 0

Answer: b. (y-12.8)=-0.8(x-14.5)

Step-by-step explanation:

We know that the equation of a line in point slope form with slope m and passing through point (a,b) is given by :-

(y-b)=m(x-a)

Given : The slope of the line : m= -0.8

The point from which line is passing : (a,b) =(14.5,12.8)

Then , the equation in point slope form of the line having the given slope that contains the given point. m=−0.8, (14.5,12.8)  :-

(y-12.8)=-0.8(x-14.5)

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first you have to find the reciprocal for 2 / 5 can do that by flipping 2 / 5 you'll then get 5 / 2 now the rest is simple all you have to do is multiply 7/12 by 2/5 so you multiply 7 by 2 and you get 14 that's your numerator 10 divide 12 by 5 and you'll get 60 so now you have 14 / 60 7 / 30 now you simplify and you get

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