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RoseWind [281]
4 years ago
11

write an equation in point-slope form of the line having the given slope that contains the given point. m=−0.8, (14.5,12.8) sele

ct one: a. y−14.5=−0.8(x−12.8) b. y−12.8=−0.8(x−14.5) c. y=−0.8x−1.2 d. y 12.8=−0.8(x−14.5)
Mathematics
2 answers:
NARA [144]4 years ago
7 0
Y - y₁ = m(x -x₁)

slope m = -0.8,  from point (14.5, 12.8) ,  x₁ = 14.5, y₁ = 12.8

 y - y₁ = m(x -x<span>₁)

</span>y - 12.8 = -0.8(x - 14.5<span>)
</span>
<span>Option B </span>
Ganezh [65]4 years ago
4 0

Answer: b. (y-12.8)=-0.8(x-14.5)

Step-by-step explanation:

We know that the equation of a line in point slope form with slope m and passing through point (a,b) is given by :-

(y-b)=m(x-a)

Given : The slope of the line : m= -0.8

The point from which line is passing : (a,b) =(14.5,12.8)

Then , the equation in point slope form of the line having the given slope that contains the given point. m=−0.8, (14.5,12.8)  :-

(y-12.8)=-0.8(x-14.5)

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Step-by-step explanation:

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7 0
3 years ago
Parallel and perpendicular line (4,7);y3x+6
enyata [817]

Answer:

Parallel Line: y = 3x - 5

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Step-by-step explanation:

The equation given is a linear equation in slope-intercept form, y = mx + b, where m = slope and b = y-intercept.  With lines that are parallel to each other, they containt the same slope.  So, to form an equation of a line that is parallel to the first equation, the slope = 3.  Using the given point (4, 7), x = 4 and y = 7, we can use our slope-intercept form to solve for 'b':

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8 0
3 years ago
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