First, we need to take the integral of ∛x+2 which is the same as x^1/3+2. To integrate the first part, we add one to the exponent and multiply by the new exponent's reciprocal to get 3/4*x^4/3. Then, the 2 would become a 2x. Now, we are finding the value of 3/4*x^4/3+2x from -1 to 1. To do this, you plug in the top value (1) first, and then subtract the result of plugging in the lower value (-1): [3/4*1^4/3+2(1)]-[3/4*(-1)^4/3+2(-1)]. This would be simplified to [3/4+2]-[3/4-2]. After distributing the negative, it becomes 3/4+2-3/4+2 or simply 4.
I hope this helps
Answer:
i think it’s d, but i’m not sure.
Explanation:
