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Jobisdone [24]
3 years ago
15

A server at the Luminous Nose restaurant goes to this same ice-cream store but decides to get a triple-decker cone. The stacking

of scoops on the cone is important: a cone with peppermint atop two scoops of squirrel tastes different than a cone with two scoops of squirrel atop a scoop of peppermint, so an order of peppermint-squirrel-squirrel is different from an order of squirrelsquirrel-peppermint. How many possible triple-decker ice-cream orders are there?
Mathematics
1 answer:
sergeinik [125]3 years ago
3 0

Answer:

Step-by-step explanation:

Lets rename the variables as

P = peppermint

S = squirrel.

Now, let's see how many different ice cream orders can we made with this two flavours.

We got 3 scoops. So we can place on the first scoop P.

And on top, we can add P P, S S, S P , or P, S.

So the Triple Decker would be ( PPP, PSS, PSP , PPS)

So we can get 4 kind of flavours with Peppermint on the first scoop.

And if we use a scoop of Squirrel on the first level. We would also have

( SPP, SSS, SSP, SPS)

So we can order 8 different ice cream orders. This is called a variation with repetition. And the math function that represents it is:

2^3

Where 2 is different variables that we can use (Pepper or Squirrel), and 3 is the number of places where we can place the variable.(the order of the scoop)

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Answer:

99% CI:

-4.637\leq\mu_v-\mu_o\leq 3.737

Step-by-step explanation:

We have to calculate a 99%CI for the difference of means for the vegan and the omnivore.

First, we have to estimate the standard deviation

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MSE=\frac{(SSE_1+SSE_2)}{df} =\frac{(n_1s_1)^2+(n_2*s_2)^2}{n_1+n_2-2}\\\\MSE=\frac{(85*1.05)^2+(96*1.20)^2}{85+96-2}=\frac{7965.56+13272.04}{179} =118.65

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\Delta M=M_v-M_o=5.10-5.55=-0.45

Then the confidence interval can be constructed as

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I thought I'd try finding roots of this function using synthetic division.  See below:

f(x) = 6x^4 – 21x^3 – 4x^2 + 24x – 35
Please use " ^ " to denote exponentiation.  Thanks.

Possible zeros of this poly are factors of 35:  plus or minus 1, plus or minus 5, plus or minus 7.  Use synthetic division; determine whether or not there is a non-zero remainder in each case.  If none of these work, form rational divisors from 35 and 6 and try them:  5/6, 7/6, 1/6, etc.

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        ----------- ------------------------------
           6        0     -4    10       0

Because the remainder is zero, 7/2 (or 3.5) is a root of the polynomial.  Thus, (x-3.5), or (x-7/2), is a factor.

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