Answer:
sum of terms: 55550
Explanation:
![\sf S_n = \dfrac{n}{2} (u_{start}+u_{end}})](https://tex.z-dn.net/?f=%5Csf%20S_n%20%3D%20%5Cdfrac%7Bn%7D%7B2%7D%20%28u_%7Bstart%7D%2Bu_%7Bend%7D%7D%29)
Here the number of terms:
1100 ÷ 11 = 100
Using the Formula:
![\sf \dfrac{100}{2} (11+1100)](https://tex.z-dn.net/?f=%5Csf%20%5Cdfrac%7B100%7D%7B2%7D%20%2811%2B1100%29)
![\sf 55550](https://tex.z-dn.net/?f=%5Csf%2055550)
Answer:
the answer is A. 47
Step-by-step explanation:
tanθ = 15/14
the answer for 15/14 comes out to be about 1.0714 and so you put that value into your calculator using the sin^-1 button. it should look something like this sin^-1(1.0714) and press enter and you'll get 46.974 and round will result in 47
Yes it is the most simplified version