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11111nata11111 [884]
4 years ago
13

Find the given elements of matrix D Please help!!!

Mathematics
2 answers:
TEA [102]4 years ago
8 0

Answer:

Element wise subtraction.

Step-by-step explanation:

Matrix Subtraction is done element wise.

Therefore, D = \[  \left[ {\begin{array}{ccc}   3 & 1 & 0 \\   -1 & 2 & 4 \\9 & 7 & -2  \end{array} } \right]\] - \[  \left[ {\begin{array}{ccc}   5 & 2 & -4\\   1 & 12 & 3 \\ 11 & 3 & -2  \end{array} } \right]\]

This becomes:

\[   D =  \left[ {\begin{array}{ccc}   -2 & -1 & 4 \\    -2 & -10 & 1 \\    -2 & 4 & 0  \end{array} } \right]\]

Now, $ d_{11} = -2 $

$ d_{12} = -1 $

$ d_{13} = 4 $

$ d_{21} = -2 $

$ d_{22} =  -10 $

$ d_{31} = -2 $

andrew-mc [135]4 years ago
4 0

Answer:-2, -1, 4, -2, -10, -2

Step-by-step explanation:

on edge 2020

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Police use a radar unit is used to measure speeds of cars on a freeway. The speeds are normally distributed with a mean of 90 km
vagabundo [1.1K]

Answer:

A. P(x≥100)=0.1587

B. P(x≤0)≈0

Step-by-step explanation:

A. Cause we know the distribution of the data, the method used to solve it is called "Normalization" and we need to have the Mean and the Standard deviation of the data. The method consist in the following equation

P(x≤a)=P( z=((x-μ)/σ) ≤ b=((a-μ)/σ) )

Considering <u>μ as the Mean</u> and <u>σ as the Standard deviation</u>. At first, we had a probability in the normal distribution with Mean=90 and STD=10 but <u>that kind of exercises is not meant to find that probability directly but by using this process</u>.

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We look for the probability that P(x≥100), but we don´t have an easy method to use there, so we normalize:

P(x≥100)=P( (x-μ)/σ ≥ (100-μ)/σ )

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P(x≥100)=P( z ≥ 1 )

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P(z≥1)=1-P(z≤1)

And finally we use the chart:

<u>the value of P(z≤1) is in the table, we look for the row with +1 and the column with the decimal part (in this case 0) and with coordinates (1,0) there´s the value</u>:

P(z≤1)=0.8413

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P(z≥1)=1-P(z≤1)

P(z≥1)=1-0.8413

P(z≥1)=0.1587

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B. We use the same process to try to understand what the probability of P(x≤0) represents.

P(x≤0)=P(z≤ (0-90)/10)

P(x≤0)=P( z ≤ -9 )

But when we try to look for its value in the chart It isn´t even there, what could it mean?

<u>A normal distribution function is always increasing</u>, that means that "a≤b if and only if P(x≤a) ≤ P(x≤b)". so we conclude:

P(z≤-9) ≤ P(z≤-3) (The lowest probability in the chart)

P(z≤-9) ≤ 0.0013

P(z≤-9) is way lower than 0.0013 (they aren´t even close) but we know that probability is always positive,  and because of that:

P(x≤0)=P(z≤-9)≈0

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