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3 years ago

Find m2ABC (3x + 8) (5x - 40)

Mathematics

1 answer:

Virty [35]3 years ago

7 0

Answer:

Step-by-step explanation:

(3x + 8) =(5x - 40)

Remove the brackets and replace 3x with -40 and -40 with 3x.

40 + 8 =5x - 3x (Remember that when you replace, the signs change from negative to positive and vise versa)

Solve for x. x= -24

Replace x with its value.

3(-24)+ 8= -64

5(-24) - 40= -160

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3 years ago

Find the average velocity of the function over the given interval.

snow_lady [41]

Answer:

Average velocity of the function over the given interval

= $log(\frac{7}{4} ) -2$

Step-by-step explanation:

Explanation:-

Given function y = 3/x -2 ...(i)

The average velocity of the function over the given interval

Average velocity = $\frac{1}{b-a} \int\limits^b_a {(\frac{3}{x} -2)} \, dx$

= $\frac{1}{7-4} \int\limits^7_4 {(\frac{3}{x} -2)} \, dx$

now integrating

= $\frac{1}{3}( \int\limits^7_4 {(\frac{3}{x} )} \, dx-2\int\limits^7_4 {1} \, dx )$

= $\frac{1}{3} (3 (log x) - 2 x )_{4} ^{7}$

= $\frac{1}{3}( (3 (log 7) - 14 )-(3 log 4 -8))$

by using formulas

log a-log b = log(a/b)

on simplification , we get

= $\frac{1}{3}( (3 (log 7) -3 log 4 ) - \frac{1}{3} (6)$

= $log(\frac{7}{4} ) -2$

Average velocity of the function over the given interval

= $log(\frac{7}{4} ) -2$

6 0

3 years ago

5. Please write the equation of a line in y=mx+b format. Find the SLOPE first then find the Y-INTERCEPT (b) Your answer

castortr0y [4]

Answer:

y = $\frac{5}{3}x-1$

Step-by-step explanation:

Let the equation of the line is,

y = mx + b

Here m = slope of the line

b = y-intercept

Slope of a line passing through two points $(x_1,y_1)$ and $(x_2,y_2)$ is,

m = $\frac{y_2-y_1}{x_2-x_1}$

From the graph attached,

Since, the given line passes through (0, -1) and (3, 4),

Slope 'm' = $\frac{4+1}{3-0}$

m = $\frac{5}{3}$

y - intercept 'b' = -1

Therefore, equation of the line will be,

y = $\frac{5}{3}x-1$

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3 years ago

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3 years ago

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