GIVEN :
a = 1/√10 ( 3i + k) and
b = 1/7 ( 2i + 3j - 6k)
TO FIND :
( 2a- b) . [ ( a x b ) x ( a + 2b)]
SOLUTION :
◆Going with the equation given,
( 2a - b) . [ ( a x b ) x ( a + 2b)]
= (2a - b) [( a×b×a) + 2(a×b)×b]
◆BAC - CAB RULE,
A×B×C = B( A.B ) - C(A.B )
= (2a- b ) [ (b (a.a ) - a (a.b ) + 2b ( a.b) -2b (a.b]
Solving further
= (2a - b )(b - 2a)
= -4a.a -b.b
=-5.
Answer:
( 2 - b) . [ ( a x b ) x ( a + 2b)] = -5
Hoped I helped
To find the answer you have to first find how many degrees are there in between each number in the clock. the clock is 360°degrees and there are 12 numbers marked in a clock., so you have to divide 360 by 12 to get the number of degrees in between each number,
360°÷12=30° so there are 30°degrees between each number.
if a clock hand moves from 12 to 5, it pass 5 numbers, so to get your final answer you have to multiply 30° by 5=150°.
so your answer is 150°degrees.
hope you can understand what i said. :)
<h2>Area of a square = side × side</h2>
Let the side = x
<h3>Length of each side = <u>8</u><u> </u><u>units</u></h3>
.... Hope this will help....
The y-value is the one on the right. Therefore, the y-value of P is 6. Following the rule, the y-value of P' is 6-16= -10.
