Please help!!!!!!!!!

You’ve been saving your money to buy a guitar. You have 3 ten-dollar bills, 8 five-dollar bills, and 26 one-dollar bills. You al

lana66690 [7]

Answer: $147.84

I had the same question and it is $147.84.

8 0

3 years ago

Read 2 more answers

How do u work out 65% of 8700

lidiya [134]

First off, you have to make 65 % into an actual number, which is 0.65 (every time you want to convert percentages into numbers, you have to divide that by 100)

Now

0.65 * 8700 = 5655

Answer: 5655

5 0

2 years ago

What is 0.8 and 5/8 and 0.01 in a percentage

vovikov84 [41]

The correct answers are:

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1) " 0.8 = 80 % " .

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2) " $\frac{5}{8}$ = 62. 5 % " .

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3) " 0.01 = 1 % " .

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Explanation:

To solve:

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Write the numbers: " 0.8 " ; " 5/8 " ; and: " 0.01 " ; as "percentages" .

To write a "number" as a "percentage" :

You take the "number" ;

Multiply that "number" by "100" ; AND:

add a "percent symbol";

→ that is: " % " ;

→ to denote the "percentage" ; or, "parts per hundred" .

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Let us start with the number: " 0.8 " .

→ " 0.8 " * 100 = ?

→ Take the decimal point, and move it 2 decimal spaces to the right; since we are "multiplying" by "100" (which has "2 zeros") ;

→ 0.8 * 100 = ? ; If we move the decimal space "one space" forward, we have: "8" . If we move the decimal space yet "one more space forward" ;

→ "8." to: " 80 " .

→ Then we add the "percent symbol":

→ " 80 " ; to: " 80 % "

Answer: " 0.8 = 80 % " .

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Other method:

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→ Note that "percentage" means: "parts per hundred" :

→ Given: " 0.8 " ; Convert to a "percentage" :

→ " 0.8 = $\frac{8}{10}$ " ;

→ " $\frac{8}{10} = \frac{?}{100}$ " ;

→ Find the "?" value.

→ To do so; look at the "denominators" :

→ " 10 * (what) = 100 " ?

→ Divide each side by "10" ;

→ " [10 * what ] / 10 = 100 / 10 " ;

→ to get:

→ " [what] " = "10" .

→ So; " $\frac{8}{10} = \frac{?}{100}$ " ;

→ If "{10 * 10 = 100}" ; then, "{8 * 10 = 80}" .

→ So; " {?} " = " 80 " .

→ So; " $\frac{8}{10} = \frac{80}{100}$ " ;

→ As such: " 0.8 " = " ( $\frac{80}{100}$ ) " ;

= " 80 " parts per hundred ;

= " 80 % " .

Answer: " 0.8 " = 80 % " .

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Now, let convert: "( $\frac{5}{8}$ )" ; into a percentage.

→ Multiply by "100" ;

→ "( $\frac{5}{8}$ )" * 100 ;

→ "( $\frac{5}{8}$ ) * ( $\frac{100}{1}$ )" ;

→ "( $\frac{(5*100)}{(8*1)}$ )" ;

→ "( $\frac{500}{8}$ )" ;

= " { 500 ÷ 8 } " ;

= " 62. 5 " ;

→ Now, add the "percent symbol" ;

→ " 62. 5 " ; → 62. 5 % " .

Answer: " $\frac{5}{8}$ = 62. 5 % " .

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Now, let us finish with our last "given value":

Convert: " 0.01 " ; to a "percentage" :

→ " 0.01 " * 100 = ?

→ Take the decimal point, and move it 2 decimal spaces to the right; since we are "multiplying" by "100" (which has "2 zeros") ;

→ 0.01 * 100 = ? ; If we move the decimal space "2 spaces forward" , we have: " 1 " .

As such:

→ " 0.01 " to: " 1 " .

→ Then we add the "percent symbol":

→ " 1 " ; to: " 1 % " .

Answer: " 0.01 = 1 % " .

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Hope this answer is of help to you.

Best wishes!

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5 0

3 years ago

Find $\int \dfrac{x}{\sqrt{1-x^4}}$ Please, help

ki77a [65]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2867785

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Evaluate the indefinite integral:

$\mathsf{\displaystyle\int\! \frac{x}{\sqrt{1-x^4}}\,dx}\\\\\\ \mathsf{=\displaystyle\int\! \frac{1}{2}\cdot 2\cdot \frac{1}{\sqrt{1-(x^2)^2}}\,dx}\\\\\\ \mathsf{=\displaystyle \frac{1}{2}\int\! \frac{1}{\sqrt{1-(x^2)^2}}\cdot 2x\,dx\qquad\quad(i)}$

Make a trigonometric substitution:

$\begin{array}{lcl}
\mathsf{x^2=sin\,t}&\quad\Rightarrow\quad&\mathsf{2x\,dx=cos\,t\,dt}\\\\
&&\mathsf{t=arcsin(x^2)\,,\qquad 0\ \textless \ x\ \textless \ \frac{\pi}{2}}\end{array}$

so the integral (i) becomes

$\mathsf{=\displaystyle\frac{1}{2}\int\!\frac{1}{\sqrt{1-sin^2\,t}}\cdot cos\,t\,dt\qquad\quad (but~1-sin^2\,t=cos^2\,t)}\\\\\\
\mathsf{=\displaystyle\frac{1}{2}\int\!\frac{1}{\sqrt{cos^2\,t}}\cdot cos\,t\,dt}$

$\mathsf{=\displaystyle\frac{1}{2}\int\!\frac{1}{cos\,t}\cdot cos\,t\,dt}\\\\\\
\mathsf{=\displaystyle\frac{1}{2}\int\!\f dt}\\\\\\
\mathsf{=\displaystyle\frac{1}{2}\,t+C}$

Now, substitute back for t = arcsin(x²), and you finally get the result:

$\mathsf{\displaystyle\int\! \frac{x}{\sqrt{1-(x^2)^2}}\,dx=\frac{1}{2}\,arcsin(x^2)+C}$ ✔

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You could also make

x² = cos t

and you would get this expression for the integral:

$\mathsf{\displaystyle\int\! \frac{x}{\sqrt{1-(x^2)^2}}\,dx=-\,\frac{1}{2}\,arccos(x^2)+C_2}$ ✔

which is fine, because those two functions have the same derivative, as the difference between them is a constant:

$\mathsf{\dfrac{1}{2}\,arcsin(x^2)-\left(-\dfrac{1}{2}\,arccos(x^2)\right)}\\\\\\
=\mathsf{\dfrac{1}{2}\,arcsin(x^2)+\dfrac{1}{2}\,arccos(x^2)}\\\\\\
=\mathsf{\dfrac{1}{2}\cdot \left[\,arcsin(x^2)+arccos(x^2)\right]}\\\\\\
=\mathsf{\dfrac{1}{2}\cdot \dfrac{\pi}{2}}$

$\mathsf{=\dfrac{\pi}{4}}$ ✔

and that constant does not interfer in the differentiation process, because the derivative of a constant is zero.

I hope this helps. =)

6 0

3 years ago

What describes the number and type of the roots of the equation 4x+7=0

Kaylis [27]

Answer:

D : One Real Root

Step-by-step explanation:

Isolate "4x" by subtracting 7 from both sides.

So we get

4x = -7

Then we divide each side by 4 to get -7/4

x = -7/4 so there is only one real root.

5 0

3 years ago