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Answer:
i. sin(C) =
ii. tan(C) =
iii. sin(B) =
Step-by-step explanation:
Given a right angled triangle ABC, with a right angle at A.
<ABC =
<BCA =
AC = 9 = 1
CB = 18 = 2
Applying Pythagoras theorem to ΔABC, we have;
AB =
=
=
Thus applying the trigonometric ratios, it would be observed that;
i. sin(C) =
ii. tan(C) =
iii. sin(B) =