question: An investment of $100 is now valued at $149.18 the interest rate is 8% per year, compounded continuously about how long has the money been invested
Answer:
5.2 years
Step-by-step explanation:
Applying
A = P(1+R/100)ⁿ.......................... Equation 1
Where A = amount, P = principle, R = rate, n = time.
From the question,
Given: A = $149.18, P = $100, R = 8%
Substitute these values into equation 1 and solve for n
149.18 = 100(1+8/100)ⁿ
149.18/100 = (1+8/100)ⁿ
1.4918 = (1+0.08)ⁿ
1.4918 = (1.08)ⁿ
Taking the Logarithm of both side
Log(1.4918) = Log(1.08)ⁿ
Log(1.4918) = nLog(1.08)
n = Log(1.4918)/Log(1.08)
n = 0.1737/0.0334
n = 5.2 years.
<u>Answer:</u>
- The value of c is 2√2 or about 2.8.
<u>Step-by-step explanation:</u>
<u>We can find the hypotenuse (c) with the help of Pythagoras Theorem.</u>
- => c² = 2² + 2²
- => c² = 4 + 4
- => c² = 8
- => c = √8
- => c = √2 x 2 x 2
- => c = 2√2
<u>If you want further simplification, seek for explanation below.</u>
- => c = 2√2
- => c = 2 x √2
- => c = 2 x 1.414
- => c = 2.828 = 2.8 (Estimated)
Hence, <u>the value of c is 2√2 or about 2.8.</u>
Hoped this helped.

Remember to make the polynomials to equal zero, one or the other polynomial must equal zero. So...
2x-3 = 0
2x= 3
x=3/2
and
4x+5 = 0
4x = -5
x = -5/4
So the answers are x=3/2 and x = -5/4
Hope this helps!
Answer:
B= (-1, 7)
Step-by-step explanation:
Midpoint formula is X1 plus X2, then divided by 2. So, because the midpoint is given you work backwards. So for the x value do (-3 + x) divided by 2 equals -2 and solve for x and you do the same thing for the Y value
Answer:
The answer to the question is
The actual duration of the trip is 8/9 times the normal duration or the bus arrived 1/9 times earlier than it would have at a constant speed of v kph
Step-by-step explanation:
Speed of bus in the first third distance = v kph
Speed of bus for the remaining two thirds = 1.2 v kph
To solve the question, we note that speed = distance/time
therefore time = distance/speed
Let the distance of the destination be D, then
Normal duration at speed v = D/v
Actual duration (D/3)÷v + (2D/3)÷(1.2v) ⇒ (1.2*D/3 + 2D/3)1.2v
=
= (8/9)×D/v
Therefore the actual duration is 8/9 times the normal duration