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Ray Of Light [21]
3 years ago
5

Tommy used benchmark fractions to estimate the sum of 1/5 +3/7 as 1. Tommy's teacher said he was incorrect. Explain what error T

ommy might have made and what tips you can give him to solve the problem correctly.
Mathematics
1 answer:
Alika [10]3 years ago
3 0

Answer:

Error made by Tommy is he didn't follow the rules of using benchmark fractions to estimate the individual fractions but just added normally and estimated to the highest whole number.

So next time he will have to estimate the individual fractions using the benchmark rules before adding up to get the approximate benchmark sum.

Step-by-step explanation:

A benchmark fraction is used to compare two or more fractions to see if they are lesser than, equal to or greater than the benchmark.

Now, in this question we want to find the benchmark of 1/5 +3/7.

In benchmarks, we have the following rules;

- if the numerator is close to zero, then the fraction is close to zero

-if the numerator is close to half of the denominator, then the fraction is close to ½.

- if the numerator is close to the denominator, then the fraction is close to 1.

Now in our question 1/5 will be closer to zero because the numerator is closer to zero.

But, 3/7 will be closer to ½ because the numerator is close to half of the denominator.

Thus,

1/5 +3/7 will be closer to 0 + ½ = ½

Thus, the correct estimate of the sum using benchmark is ½

Error made by Tommy is he didn't follow the rules of using benchmark fractions to estimate the individual fractions but just added normally and estimated to the highest whole number.

So next time he will have to estimate the individual fractions using the benchmark rules before adding up to get the approximate benchmark sum.

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<h3>What is an array (area) multiplication model?</h3>

An array representation of a multiplication is a rectangular visual order of positioning of rows and columns that indicates the terms of a multiplication equation.

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The terms of the equation represented by the model are indicated by the two columns of length one ninth each shaded grey and the three rows of width one fourth each covered with dots, such that the equation can be presented as follows;

\left(\dfrac{1}{9} +\dfrac{1}{9}\right) \times \left(\dfrac{1}{4} +\dfrac{1}{4} + \dfrac{1}{4} \right) = \dfrac{2}{9} \times \dfrac{3}{4} =\dfrac{6}{36}

The equation that the model represents is therefore;

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