Answer:
The fossil is 1860 years old.
Step-by-step explanation:
The equation for the amount of fossil has the following format:

In which Q(t) is the amount after t years, Q(0) is the initial amount and r is the rate of change.
Half-life of c-14 is 5730 years.
This means that 
So







So

How old is the fossil?
This is t for which

So







The fossil is 1860 years old.
Answer:
vol=BX1/3 h
=64* 1/3 square root of 32
Step-by-step explanation:
Step-by-step explanation:
![\sqrt[8]{ {x}^{2} {y}^{6} } \\ \\ = ( {x}^{2} {y}^{6} )^{ \frac{1}{8} } \\ \\ = {x}^{2 \times \frac{1}{8}} {y}^{6\times \frac{1}{8}} \\ \\ = x^{\frac{1}{4}} {y}^{3\times \frac{1}{4}} \\ \\ = x^{\frac{1}{4}} {y}^{\frac{3}{4}} \\ \\ = \sqrt[4]{x {y}^{3} } \\](https://tex.z-dn.net/?f=%20%5Csqrt%5B8%5D%7B%20%7Bx%7D%5E%7B2%7D%20%20%7By%7D%5E%7B6%7D%20%7D%20%20%5C%5C%20%20%5C%5C%20%20%3D%20%28%20%7Bx%7D%5E%7B2%7D%20%7By%7D%5E%7B6%7D%20%20%29%5E%7B%20%5Cfrac%7B1%7D%7B8%7D%20%7D%20%20%5C%5C%20%20%5C%5C%20%20%3D%20%20%7Bx%7D%5E%7B2%20%5Ctimes%20%5Cfrac%7B1%7D%7B8%7D%7D%20%7By%7D%5E%7B6%5Ctimes%20%5Cfrac%7B1%7D%7B8%7D%7D%20%20%5C%5C%20%20%5C%5C%20%20%3D%20x%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%20%7By%7D%5E%7B3%5Ctimes%20%5Cfrac%7B1%7D%7B4%7D%7D%20%20%5C%5C%20%20%5C%5C%20%20%20%3D%20x%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%20%7By%7D%5E%7B%5Cfrac%7B3%7D%7B4%7D%7D%20%20%5C%5C%20%20%5C%5C%20%20%20%3D%20%20%5Csqrt%5B4%5D%7Bx%20%7By%7D%5E%7B3%7D%20%7D%20%20%5C%5C%20)
Answer:
36-54i
Step-by-step explanation:
(9+9i)(-1-5i)
v
-9-9×5i-9i-9i×5i
v
-9-45i-9i-45i^2
v
-9-45i-9i-45×(-1)
v
(-9)-45i-9i+(45)
v
36(-45i)(-9i)
v
36-54i
Answer:
(5r - 20)
Step-by-step explanation:
(3r + 14) + (Ar + B) = (8r - 6)
B = -6 - 14 = -20
A = 8 - 3 = 5