Answer:
a) P(z<-0.66) = 0.2546
b) P(-1<z<1) = 0.6826
c) P(z>1.33) = 0.9082
Step-by-step explanation:
Mean = 300
Standard Deviation = 75
a) Less than 250 hours
P(X<250)=?
z = x - mean/ standard deviation
z = 250 - 300 / 75
z = -50/75
z = -0.66
P(X<250) = P(z<-0.66)
Looking for value of z = -0.66 from z score table
P(z<-0.66) = 0.2546
b. Between 225 and 375 hours
P(225<X<375)=?
z = x - mean/ standard deviation
z = 225-300/75
z = -75/75
z = -1
z = x - mean/ standard deviation
z = 375-300/75
z = 75/75
z = 1
P(225<X<375) = P(-1<z<1)
Looking for values from z score table
P(-1<z<1) = P(z<1) - P(z<-1)
P(-1<z<1) = 0.8413 - 0.1587
P(-1<z<1) = 0.6826
c. More than 400 hours
P(X>400) =?
z = x - mean/ standard deviation
z = 400-300/75
z = 100/75
z = 1.33
P(X>400) = P(z>1.33)
Looking for value of z = 1.33 from z-score table
P(z>1.33) = 0.9082
The answer is -3yx(-y-3x)
Answer:4 hours an 40 minutes
Step-by-step explanation: i started out adding the hours together so the class started at 6:45 the 7:45 then 8:45 then 9:45 then i had to stop there an add 15 minutes to get to 10:00 then i adding another 25 minutes to get to 10:45
Answer:
The algebraic equation describing the above
X+y= x-30
Step-by-step explanation:
The initial temperature of the environment= x degrees
Temperature of the front= y degrees
the environment dropped 30 degrees, means loosed 30 degrees.
The final temperature f the environment= x-30
The algebraic equation describing the above
X+y= x-30
12 I think if I’m wrong sorry! If I’m right please mark my brainly
